Y = 1 3 -x = left[y \right] = \left[ 3-x\right][y]=[3−x]
Answer:
x <5
Step-by-step explanation:
2(4 x + 3) < 5 x + 21
Distribute
8x +6 < 5x +21
Subtract 5x from each side
8x -5x +6 < 5x-5x+21
3x +6 < 21
Subtract 6 from each side
3x+6-6 <21-6
3x <15
Divide each side by 3
3x/3 <15/3
x <5
Step-by-step explanation:
the probability is always the number of desired cases over the number of all possible cases.
in our situation we have 15 cards.
that is the total possible cases when a random card is chosen.
how many desired cases do we have ?
a number NOT a multiple of 5.
how many are there ?
it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15
so, 3 numbers out of the 15 are multiple of 5.
that means
15 - 3 = 12 numbers of the 15 are NOT multiples of 5.
so, the probability to draw a card that is not a multiple of 5 is
12/15 = 4/5 = 0.8
the information about event B and even numbers is irrelevant for the question.