Hello There!
<u><em>The number of adult tickets sold in the school play = 225</em></u>
<u><em></em></u>
<u><em>Total Number Of Tickets = 505</em></u>
<u><em>Number Of Student Tickets = x + 55</em></u>
<u><em></em></u>
Number of adult tickets sold can be represented by X
Number of student tickets = X + 55
X+X+55=505
2x+55=505
2x=505-55
2x=450
X=225
Answer:
a) JK is a secant line
b) IE is a chord
c) GH is a tangent line
Step-by-step explanation:
Answer:
52.5% probability that A occurs given B occurs
Step-by-step explanation:
Suppose we have two events, A and B, the conditional probability formula is:
![P(A|B) = \frac{P(A \cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%7CB%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28B%29%7D)
In which
P(A|B) is the probability of A happening given that B happened.
is the probability of both A and B happening.
P(B) is the probability of B happening.
In this problem, we have that:
![P(A \cap B) = \frac{3}{8}, P(B) = \frac{5}{7}](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%20%5Cfrac%7B3%7D%7B8%7D%2C%20P%28B%29%20%3D%20%5Cfrac%7B5%7D%7B7%7D)
So
![P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{\frac{3}{8}}{\frac{5}{7}} = 0.525](https://tex.z-dn.net/?f=P%28A%7CB%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28B%29%7D%20%3D%20%5Cfrac%7B%5Cfrac%7B3%7D%7B8%7D%7D%7B%5Cfrac%7B5%7D%7B7%7D%7D%20%3D%200.525)
52.5% probability that A occurs given B occurs
Answer:
.
Step-by-step explanation: We are given expression
.
And
expression is converted in
.
Now, we need to transform the expression into a single exponent expression using the properties of exponents.
We know, according to the properties of exponents
![(a^m)^n = a^{m\times n}](https://tex.z-dn.net/?f=%28a%5Em%29%5En%20%3D%20a%5E%7Bm%5Ctimes%20n%7D)
Applying same rule in given expression, we get
![(1.06^{1/2})^{2t} = (1.06)^{\frac{1}{2} \times 2t}](https://tex.z-dn.net/?f=%281.06%5E%7B1%2F2%7D%29%5E%7B2t%7D%20%3D%20%281.06%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%202t%7D)
On simplifying exponents, we would get t in exponent.
=
.