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3 years ago

Which expression is equivalent to 1/2b-15

Mathematics

1 answer:

Helen [10]3 years ago

3 0

Answer:

b/2-15

-15+1/2b

b:2-15

Step-by-step explanation:

which expression is equivalent to 1/2b-15

b/2-15

-15+1/2b

b:2-15

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Let me know the answer plz

Gala2k [10]

<u>Answer:</u>

The correct answer option is H. 4374.

<u>Step-by-step explanation:</u>

We are given the following geometric sequence and we are to find its 8th term:

$\frac{2}{9}, \frac{2}{3}, 2,...$

Here $a_1=\frac{2}{9}$ and common ratio $(r) = \frac{\frac{2}{3} }{\frac{2}{9} } =3$ .

The formula we will use to find the 10th term is:

nth term = $a_1 \times r^{(n-1)}$

Substituting the values in the formula to get:

10th term = $\frac{2}{9} \times 3^{(10-1)}$

10th term = 4374

7 0

3 years ago

What is the sum of 6x3+8x2-2x+4 and 10x3+x2+11x+9

AleksAgata [21]

Answer:

16x³ + 9x² + 9x + 13

Step-by-step explanation:

Given

6x³ + 8x² - 2x + 4 and 10x³ + x² + 11x + 9

Sum the 2 expressions by adding like terms, that is

= (6x³ + 10x³) + (8x² + x²) + (- 2x + 11x) + (4 + 9)

= 16x³ + 9x² + 9x + 13

4 0

3 years ago

Is the square root of 222 rational number

nignag [31]

Answer:

The square root of 222 is an irational number.

7 0

3 years ago

Read 2 more answers

The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds

boyakko [2]

The rock will hit the ground at 2 seconds.

Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation $h=-16t^2+24t+16$ , where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation $h=-16t^2+24t+16$ , we get,

$0=-16t^2+24t+16$

Switch sides, we have,

$-16 t^{2}+24 t+16=0$

Let us solve the equation using the quadratic formula.

Thus, we have,

$t=\frac{-24 \pm \sqrt{24^{2}-4(-16) 16}}{2(-16)}$

Simplifying, we get,

$t=\frac{-24 \pm \sqrt{576+1024}}{-32}$

$t=\frac{-24 \pm \sqrt{1600}}{-32}$

$t=\frac{-24 \pm 40}{-32}$

Hence, the two values of t are

$t=\frac{-24 + 40}{-32}$ and $t=\frac{-24 -40}{-32}$

Simplifying the values, we get,

$t=\frac{16}{-32}$ and $t=\frac{-64}{-32}$

Dividing, we get,

$t=-\frac{1}{2}$ and $t=2$

Since, t cannot negative values, we have,

$t=2$

Thus, the rock will hit the ground at 2 seconds.

8 0

3 years ago

What’s the volume of a cone with the radius of 45 cm and a height of 55 cm

viva [34]

The answer is 116631.6 if rounded it is 116632

3 0

3 years ago