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3 years ago

Niko uses 12 marshmallows and 8 graham crackers to make 4 s'mores.

Mathematics

2 answers:

sleet_krkn [62]3 years ago

6 0

Answer:

The answer is 6 crackers and 9 marshmallows

Step-by-step explanation

:You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:

8 / 4 = 2, so 2 crackers per s'more. Then,

12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.

2 * 3 = 6, so 6 crackers, and

3 * 3 = 9, so 9 marshmallows.

Lerok [7]3 years ago

3 0

Answer:

6 crackers, 9 marshmallows

Step-by-step explanation:

You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:

8 / 4 = 2, so 2 crackers per s'more. Then,

12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.

2 * 3 = 6, so 6 crackers, and

3 * 3 = 9, so 9 marshmallows.

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A package of 30 Oreos cost $3.60. Kennedy says the unit rate is 0.12. Mason says the unit rate is 8.33. Who is right?

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Answer:

$360 \div 30 = 12$

Step-by-step explanation:

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2 years ago

While looking at some reports, a store manager notes that televisions that retail for $475 and up costing customers $513 once th

Mekhanik [1.2K]

The sales tax percentage of the store manager report is 7.41%

<h3>How to solve for the sales tax percentage</h3>

Customers are subject to a charge known as sales tax when they buy goods and services.

It is a pass-through tax, which means you must collect it from clients and send the money to your state or local government. the seller do not contribute sales tax.

The sales tax is first calculated by

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sales tax percentage is calculated using the formula

= (Tax amount / Price before tax) × 100%

= (38 / 513) * 100

= 7.4074

= 7.41%

Learn more about sales tax at:

brainly.com/question/20220356

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1 year ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$