If there are 6 stacks with 2 cans in each stack, then you would times 6 x 2 = 12
Answer:
Lose $0.05
Step-by-step explanation:
There are 38 possible spots on the roulette wheel (numbers 1 to 36, 0 and 00).
If the player can choose four numbers on single $1 bet, his chances of winning (W) and losing (L) are as follows:

The expected value of the bet is given by the probability of winning multiplied by the payout ($8), minus the probability of losing multiplied by the bet cost ($1)

On each bet, the player is expected to lose 5 cents ($0.05).
Answer:
#1: No #2: Yes #3: Yes #4: Yes
Linear Equation: 15m+10=w
15 pages written for every month for 5 months plus the 10 pages she has already written is equal to the total number of pages written in 5 months.
m= number months written. In this case, it is 5 months.
w= number of pages written in 5 months
15(5)+10=w
75+10=w
85 pages written=w
Carla will have written 85 pages in 5 months.
9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
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B. The second row of A represents the second equation:

The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)