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Molodets [167]
3 years ago
13

What is 7|t| – 4|m|, if t = –4 and m = –1? A. 32 B. 24 C. –24 D. –32

Mathematics
1 answer:
Misha Larkins [42]3 years ago
5 0

Answer:

the answer is a

Step-by-step explanation:

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Please help! How do I solve this?
Advocard [28]
m\angle 6=m\angle3\\
8x+7=6x+32\\
2x=25\\
x=12.5\\\\
m\angle 6=8\cdot12.5+7=100+7=107\Rightarrow D

5 0
3 years ago
What is the quotient?
yuradex [85]

Answer:

-1.58208955224

Step-by-step explanation:

DO THE MATH

5 0
2 years ago
The average daily rainfall for the past week in the town of Hope Cove is normally distributed, with a mean rainfall of 2.1 inche
natita [175]

Answer:

D

Step-by-step explanation:

We calculate the z-score for each

Mathematically;

z-score = (x-mean)/SD

z1 = (1.9-2.1)/0.2 = -1

z2 = (2.3-2.1)/0.2 = 1

So the proportion we want to calculate is;

P(-1<x<1)

We use the standard score table for this ;

P(-1<x<1) = P(x<1) -P(x<-1) = 0.68269 which is approximately 68%

6 0
2 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
What is the solution of the equation<br> √3x+2=√2x-2
MakcuM [25]

Step-by-step explanation:

\sqrt{3 x -  \sqrt{2x = 4} }

7 0
2 years ago
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