<span>0.00996 would be it I just took a quiz like that but good luck</span>
The conditional probability that the person has the disease given that the test result is positive is of 0.4750 = 47.50%.
<h3>What is Conditional Probability?</h3>
Conditional probability is the probability of one event happening, considering a previous event. The formula is:
![P(B|A) = \frac{P(A \cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D)
In which:
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem, the events are:
- Event B: Has the disease.
The percentages associated with a positive test is:
- 93.9% of 3.8%(has the disease).
- 4.1% of 100 - 3.8 = 96.2%(does not have the disease).
Hence:
![P(A) = 0.939(0.038) + 0.041(0.962) = 0.075124](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.939%280.038%29%20%2B%200.041%280.962%29%20%3D%200.075124)
The probability of both a positive test and having the disease is given by:
![P(A \cap B) = 0.939(0.038) = 0.035682](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.939%280.038%29%20%3D%200.035682)
Hence the conditional probability is given by:
![P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.035682}{0.075124} = 0.4750](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20%5Cfrac%7B0.035682%7D%7B0.075124%7D%20%3D%200.4750)
More can be learned about conditional probability at brainly.com/question/14398287
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Answer:
![\frac{111}{190}](https://tex.z-dn.net/?f=%5Cfrac%7B111%7D%7B190%7D)
Step-by-step explanation:
Answer: B
Step-by-step explanation:
Using the distance formula, we get the height is
.
Similarly, we get the base is
.
So, the area is ![\frac{1}{2}(4\sqrt{2})(6\sqrt{2})=24](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%284%5Csqrt%7B2%7D%29%286%5Csqrt%7B2%7D%29%3D24)