Ask question

Ask question

All categories

3 years ago

9

What is 3729divided by 5

2 answers:

ollegr [7]3 years ago

8 0

I think it's 745 remainder 4

Verizon [17]3 years ago

6 0

You could use a calculator, but....
The answer is 745.8
(But you might not have a calculator)

You might be interested in

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

2 years ago

Two parralel lines are cut by a transveral what is the measure of 8

dexar [7]

Answer:

its B... i think(sub2pewdiepie)

Step-by-step explanation:angle 4 is 100 degrees and 4 and 8 are corresponding

8 0

2 years ago

Read 2 more answers

Line RS bisects PQ at point R. Find RQ if PQ = 4 3/4

svetlana [45]

PQ is bisected by RS at R. It means that PRQ is a line segment with PR = RQ and each of half of PQ.

RQ = PQ/2 = 1/2 [ 4 3/4 ] = 1/2 * 19/4 = <em>19/8 </em> = 2 3/4

8 0

3 years ago

Read 2 more answers

Find the value of x and y

Natalija [7]

Hello and Good Morning/Afternoon:

<u>Let's take this problem step-by-step</u>:

<u>What does the information want:</u>

value of x
value of y

<u>Let's gather some information</u>:

ΔA'BC' and ΔABC are similar triangles

⇒ Angle B is shared by both triangles

⇒ Angle A' and A are the same, as they are both on parallel

lines, A'C' and AC, and both angles are formed with the

same line AB

⇒ by the <em>Angle-Angle Theorem*</em>, they are similar triangles

<u>If they are similar triangles</u>:

⇒ their side lengths are proportional to each other

let's find x's value

⇒ let's set up a proportion

$\frac{A'B}{AB} =\frac{A'C'}{AC} \\\frac{30}{x+30} =\frac{14}{22} \\14(x+30) = 30*22\\14x + 420 = 660\\14x = 240\\x = 17.143$

let's find y's value

⇒ let's set up a proportion

$\frac{BC'}{BC} =\frac{A'C'}{AC} \\\frac{y}{y+15} =\frac{14}{22} \\22y=14(y+15)\\22y=14y+210\\8y=210\\y=26.25$

<u>Answer:</u>

<u>x= 17.143</u>
<u>y = 26.25</u>

Hope that helps!

#LearnwithBrainly

5 0

1 year ago

In algerbra we use an blank to represent a varible

Juli2301 [7.4K]

Answer:

We use letters to represent a variable in expressions. I hope this helps!

Step-by-step explanation:

3 0

2 years ago