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3 years ago

Find the approximate surface area of the cylinder below. Round your answer to the nearest tenth.

Mathematics

2 answers:

Vinil7 [7]3 years ago

8 0

Answer:

The answer to your question is 5cm

Step-by-step explanation:

ANTONII [103]3 years ago

4 0

5cm I think, I’m just answering because Brainly wants me to

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Classify the system correctly <br> Y = 5x +2<br> 10x - 2y = 12

s344n2d4d5 [400]

Answer:

It's a simultaneous equation because it as two solution

Step-by-step explanation:

5 0

4 years ago

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Which is the value of the expression (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed?

Flura [38]

Answer:

The value to the given expression is 8

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3$

To find the value of the given expression:

$\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}$

( By using the property ( $(\frac{a}{b})^m=\frac{a^m}{b^m}$ )

$=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}$

( By using the property $(ab)^m=a^mb^m$ )

$=\frac{(10^{12})(5^6)}{(10^9)(5^9)}$

( By using the property $(a^m)^n=a^{mn}$ )

$=(10^{12})(5^6)(10^{-9})(5^{-9})$

( By using the property $\frac{1}{a^m}=a^{-m}$ )

$=(10^{12-9})(5^{6-9})$ (By using the property $a^m.b^n=a^{m+n}$ )

$=(10^3)(5^{-3})$

$=\frac{10^3}{5^3}$ ( By using the property $a^{-m}=\frac{1}{a^m}$ )

$=\frac{1000}{125}$

$=8$

Therefore $\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8$

Therefore the value to the given expression is 8

3 0

3 years ago

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Subtract 5x^2-2x-55x 2 −2x−5 from -2x^2-5x-7−2x 2 −5x−7.

leva [86]

Answer:

7x^2 -128x -19

Step-by-step explanation:

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3 years ago

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What is the number below that subtracted 7 from four times it multiplied and equals 1?

Dvinal [7]

Answer:

a.4

Step-by-step explanation:

because

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3 years ago

After the 4th half life how much of the sample is left if the mass is 100g.

vazorg [7]

Answer:

$\huge\boxed{\sf 6.25 \ g}$

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

$\rule[225]{225}{2}$

Hope this helped!

6 0

2 years ago