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Rudik [331]
2 years ago
13

Determine if the statement is always, sometimes, or never true.The opposite angles of a parallelogram are congruent.alwayssometi

mesnever
Mathematics
2 answers:
ehidna [41]2 years ago
3 0

That's true. Opposite sides of a parallelogram are parallel, which implies that the opposite angles are congruent.

n200080 [17]2 years ago
3 0

Answer: Always true.

Step-by-step explanation:

Given statement : The opposite angles of a parallelogram are congruent.

  • A parallelogram is a kind of quadrilateral having four sides in which opposite sides and angles are congruent.

Therefore, the given statement " The opposite angles of a parallelogram are congruent." is always true by the definition of parallelogram.

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NEED Help!<br> 111=14g<br> and also 13.65=h + 4.88
crimeas [40]

Answer:

In this question if g and h is constant then;

111 = 14g

14g = 111

g = 111/14

g = 27.7 ~ 28

And also,

13.65 = h + 4.88

h + 4.88 = 13.65

h = 13.65 - 4.88

h = 8.77

Hope it helps!

3 0
2 years ago
a construction company charges $15 per hour for debris removal , plus a one -time fee for the use of the trash dumpster.the tota
ser-zykov [4K]

Let h be the numbers of hours, f be the one-time fee and c the cost charged. The equation is

c=15h+f

Since you pay $15 per four, plus the fee. We can solve this equation for the fee:

f=c-15h

If we plug c=195 and h=9, we have

f=195-15\cdot 9=195-135=60

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2 years ago
Approximately how many strides does it take to complete a marathon?<br> Choose 1 answer:
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Female steps:62,926
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2 years ago
Read 2 more answers
A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha
8_murik_8 [283]
To model this situation, we are going to use the decay formula: A=Pe^{rt}
where 
A is the final pupolation
P is the initial population 
e is the Euler's constant
r is the decay rate 
t is the time in years

A. We know for our problem that the initial population is 1,250, so P=1250; we also know that after a year the population is 1000, so A=1000 and t=1. Lets replace those values in our formula to find r:
A=Pe^{rt}
1000=1250e^{r}
e^{r}= \frac{1000}{1250}
e^{r}= \frac{4}{5}
ln(e^{r})=ln( \frac{4}{5} )
r=ln( \frac{4}{5} )
r=-02231

Now that we have r, we can write a function to model this scenario:
A(t)=1250e^{-0.2231t}.

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C. 
- The function is decreasing
- The function doe snot have a x-intercept 
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0: 
A(0)=1250e^{(-0.2231)(0)
A_{0}=1250e^{0}
A_{0}=1250
- Over the interval [0,10], the function will have a minimum at t=10:
A(10)=1250e^{(-0.2231)(10)
A_{10}=134.28

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: m= \frac{A(0)-A(10)}{10-0}
where 
m is the rate of change 
A(10) is the function evaluated at 10
A(0) is the function evaluated at 0
We know from previous calculations that A(10)=134.28 and A(0)=1250, so lets replace those values in our formula to find m:
m= \frac{134.28-1250}{10-0}
m= \frac{-1115.72}{10}
m=-111.572
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0
2 years ago
A gigantic 25.6 ft. anaconda was seen in a cave by workers at a construction site in Brazil.
Arada [10]

Answer:

12 30

Step-by-step explanation:

7 0
2 years ago
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