An equation that represents the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling is S = 10 - 2t
In this question, there was a depth of 10 inches of snow on the lawn when the storm ended and then it started a melting at a rate of 2 inches per hour.
We need to write an equation for S in terms of t, snow representing the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling.
So, the equation would be,
S = 10 - 2t
Therefore, an equation that represents the depth of snow on Audrey's lawn, in inches, t hours after the snow stopped falling is S = 10 - 2t
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0.06 or you can just put 6.
Basically, you have to multiply 30% x 20.
Glad I could help☺️
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
Step-by-step explanation:
it's answer is 49........
D. 226.08cm^2
Since we are finding the combined area of the two bases of the cylinder, we are adding the area of the first base with the second base. The formula for the base of a cylinder is pi x r^2, since it is a circle. Since the bases are the same, we can rewrite this as 2pi x r^2.
Since the diameter is 12cm and r = 1/2 diameter, r = 6cm.
Thus, A = 2(3.1415)(6)^2 = 226.08cm^2
