Question

Graph the line for y+1=−3/5(x−4) on the coordinate plane.

Answer 1

Please enclose that -3/5 in parentheses:  y+1= (−3/5)(x−4)

Let's use the intercept method to graph this line.
First, set x = 0 and find y; this y will be the y-coordinate of the vertical intercept:

y+1= (−3/5)(0−4)  =>  y = -1 + 12/5 = -5/5 + 12/5 = 7/5.  Plot (0, 7/5).

Next, set y = 0 and find x; this will give us the coordinate of the horiz. int.:

0+1= (−3/5)(x−4) => -5/3 = x - 4, or x = 4- 5/3, or  x = 7/3.  Plot (7/3, 0).

Now draw a straight line thru these two points.

Answer 2

Answer:

See the graph.

Step-by-step explanation:

We have a point-slope equation

$y+1=-\frac{3}{5} (x-4)$

Point-slope is a specific form of linear equations in two variables:

$y-b=m(x-a)$

When an equation is written in this form, m gives the slope of the line and (a, b) is a point the line passes through.

Slope is a measure of the steepness of a line.

We can tell that the corresponding line passes through (4, -1) and has slope of $-\frac{3}{5}$. Now we can graph the line: