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3 years ago

I need help ASAP on number 8 b and c. Thank you

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

6 0

I think you're having trouble because the equation you wrote for 8a has a slight typo.

The question says that the length is 9 less than twice the width. Your equation states the length is 9 times the width minus 2. So the length actually equals 2w – 9, meaning that w(2w – 9) = 180

Hope this helps! If you're still having trouble, let me know :)

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120-2x=30, what’s x?

KiRa [710]

Step-by-step explanation:

-2x=30-120

-2x = -90

=x = -90/-2

=x = +45

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3 years ago

Identify the effect on the graph of replacing f(x) by f(x - h)

Tresset [83]

Given:

Replace f(x) by f(x - h).

To find:

The effect on the graph of replacing f(x) by f(x - h).

Solution:

Horizontal shift is defined as:

If the graph f(x) shifts h units left, then f(x+h).

If the graph f(x) shifts h units right, then f(x-h).

Where, h is a constant that represents the horizontal shift.

In the given problem f(x) is replaced by f(x - h) and we need to find the effect on the graph.

Here, we have x-h in place of x.

Therefore, the graph of f(x) shifts h units right to get the graph of f(x-h).

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3 years ago

Describe and correct the error(s) made in each of the problems below.

ladessa [460]

Answer:

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

$1-x / (5-x)(-x)=x-1 / x(x-5)$

Let's arrange into format:

$\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}$

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

Now for the second expression

$5/s+2/5=2/s$

Let's arrange into format

$\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}$

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

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3 years ago

Find the angles marked with letters. <br>Please help!!

Paladinen [302]

A=34°
B=76°
C and d = 70°
because a triangle is 180° and we know
a+b+c=180
76+34=110
180-110=70

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2 years ago

Which of the binomials below is a factor of this trinomial?

Tamiku [17]

None of those answers are correct sadly.

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