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2 years ago

13

The carnival is in town for 21 days. How many weeks is the carnival in town?(There are 7 days in 1 week.) Write and equation,and

solve.

1 answer:

Elza [17]2 years ago

4 0

Answer:

egn= 7x=y

where x= weeks no.

y= days

atq...x= 3

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Two liquids Kaylin mixed two liquids for science experiment one container had 7/8 Cup and the other health 9/10 cup what is the

seraphim [82]

Answer:

Step-by-step explanation:

<em>Step 1: Determine quantity per liquid</em>

liquid 1=7/8 cup

liquid 2=9/10 cup

<em>Step 2: Derive expression to calculate total amount of mixture</em>

The expression below can be derived;

T=a+b

where;

T=total amount of mixture

a=total amount of liquid 1

b=total amount of liquid 2

In our case;

a=7/8 cup

b=9/10 cup

replacing;

T=(7/8)+(9/10)=1 31/40 cups

The total amount of mixture=1 31/40 cups

3 0

2 years ago

Given the following diagram, enter the required information.

Verizon [17]

∠СXA = ∠BXA + ∠СXB = 30°20' + 40°35' = 70°55'

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3 years ago

Help? pls? (10 points) (image down below to make it easier to understand.)

dusya [7]

This is middle school??? AinT no way

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2 years ago

Read 2 more answers

48 is what percent of 40?

vlada-n [284]

Answer:

120%

Step-by-step explanation:

The ratio you are solving is 48/40

Divide the numerator by the denominator just like you would do with any other fraction.

48÷40=1.2

Your answer is 120%

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3 years ago

Read 2 more answers

Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t

Elden [556K]

Answer: a) $\bold{\dfrac{3}{16}}$ b) $\bold{\dfrac{1}{36}}$

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

2) Even, Even, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

3) Odd, Odd, Odd, Odd $\dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}$

<em>Order doesn't matter</em>

Add them up to get your answer: $\dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}$

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

$\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}$

3 0

3 years ago