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2 years ago

13

The carnival is in town for 21 days. How many weeks is the carnival in town?(There are 7 days in 1 week.) Write and equation,and

solve.

1 answer:

Elza [17]2 years ago

4 0

Answer:

egn= 7x=y

where x= weeks no.

y= days

atq...x= 3

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Devon studied the composite figure.

Nat2105 [25]

If we look at his calculations
2((9)(20) is the front an back rectangle
2((9)(34)) is the side rectangles
(34)(20) is the bottom
2(1/2(20(24)) is te front and top triangles
and the last one assumes that they are triangles which is incorrect

answer is D

8 0

2 years ago

Read 2 more answers

Find the value of sec(theta°)cos(theta°) for the following values of theta. <br> b. theta = 225

Nesterboy [21]

Answer:

sec(theta°)cos(theta°) = 1

Step-by-step explanation:

given data

(theta°) = 225

to find out

sec(theta°)cos(theta°)

solution

as we know that given equation

(theta°) = 225

cos(theta°) will be

cos(225°) = -0.7071 .................................1

so we know

sec(theta°) = $\frac{1}{cos(theta)}$ ..............2

so put here value of cos(theta°)

sec(theta°) = $\frac{1}{-0.7071}$

sec(theta°) = - 1.4142

so

sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )

sec(theta°)cos(theta°) = 1

so answer is sec(theta°)cos(theta°) = 1

8 0

3 years ago

11 less than a number is more than seventeen

Tasya [4]

17∠x-11 set up the equation like this
28∠x add 17 to the other side, and you get x is greater than 28

3 0

2 years ago

Find the mean of the data in the bar chart below.

Snowcat [4.5K]

<h2>Answer:</h2>

12

<h2>Step-by-step explanation:</h2>

<u><em>The mean is also the average.</em></u>

Add up all the number of students all together:

12+13+14+9

48

Now, Divide the total amount of students (48) by the amount of numbers you added (in this case, 48/4 because we added 4 numbers wich are 12+13+14+9)

The average amount of students is 12

7 0

2 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

$(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0$

Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

8 0

2 years ago