All categories

3 years ago

What is the probability a 1-6 number cube lands on a composite number? 0.25 0.33 0.50 0.875

2 answers:

6 0

A compsite number is a number that is NOT prime
technically 1 is not prime since the definition is divisible by 1 and itself
2 is prime
3 is prime
4 is not prime
5 is prime
6 is not prime

2 solutions for 2 different views:
A: 1 is prime
B: 1 is not prime

A: 1 is prime
so we have 1,2,3,5 are prime and 5 and 6 are not
probablity is (desired outcomes)/(total possible outcomes)
desired outcomes=2 (5 and 6)
total possible outcomes=6 (6 numbers on cube)
2/6=1/3=0.33
probabiligy is 0.33

B: 1 is not prime
if 1 is not prime then we have 2,3,5 as prime and 1,4,6 as not prime
probability is (desired outcomes)/(total possible outcomes)
desired outcomes=3 (1,4,6)
total posible outcomes=6 (6 faces on cube)
3/6=1/2=0.5
the probability is 0.5

TECHNICALLY 1 is not prime so the answe ris 0.5

sineoko [7]3 years ago

3 0

Answer=0.5

To find probability, we must find out the chances of rolling and even number. Out of the 6 sides on a dice, only 3 are even. So 3/6 are even

3/6=0.5

You might be interested in

Which inequality is equivalent to this one? y-85-2 y-8+82-2+8 oy- 8+8

vladimir2022 [97]

Answer:

The answer is the forth one , Y-8+2⩽-2+2

5 0

3 years ago

Question 12 (2 points)

Leviafan [203]

Solving is :
X=2
Y=1

Step by step
(2x-3) + 5 = 3x
2x+2=3x
X=2

Substitute x by 2
Y=1

5 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago

I GIVE BRAILILSET\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Katyanochek1 [597]

Answer:

Step-by-step explanation:

7 0

3 years ago

Can somebody help me with this please!!

saul85 [17]

1. -21

2. −39

3.−42

4. -5

5. −3

for the other question u can use calculator :)

8 0

2 years ago