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sergejj [24]
4 years ago
9

in mathematics competition,the winner won $100 more than twice the amount won by the runner-up. how much money did the runner-up

win if both of them won $2,350 altogether​
Mathematics
2 answers:
11111nata11111 [884]4 years ago
3 0

Answer:

1,175

I only halfed it.

Hope it's right.

laiz [17]4 years ago
3 0

Answer:

$750

Step-by-step explanation:

Since there are two people who won prize money and the total amount won is $2,350, we can set up an equation based on the verbal descriptions to assign a variable and solve.

Let 'x' = the amount won by the runner-up

Since the winner won '$100 more than twice the amount won by the runner-up':  winner = 2x + 100

The sum of the amount is $2,350, so:

x + (2x + 100) = 2350 or 3x + 100 = 2350

Subtract 100 from both sides:  3x + 100 - 100 = 2350 - 100 or 3x = 2250

Divide by 3 on both sides: 3x/3 = 2250/3

Solve for x:  x = $750

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dem82 [27]

Answer:

$2.00

Step-by-step explanation:

8 times 6= 56

58 - 56= 2

5 0
3 years ago
Solve the equation below:<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7B1.2%7D%20%3D%206" id="TexFormula1" title=" \
Mariulka [41]
We need to cross multiply.

\frac{a}{b} =  \frac{c}{d}

= \frac{a}{b} \times bd= \frac{c}{d} \times bd

ad=bc

So your question is:
\frac{d}{1.2}=6

This can also be written as:
\frac{d}{1.2} = \frac{6}{1}

So if we cross multiply, we will get

d \times 1 = 1.2 \times 6

d= 7.2
8 0
3 years ago
Read 2 more answers
Square root of 144 X^7 Y^5
LekaFEV [45]
The first step to solving this is to factor out the first perfect square
\sqrt{12^{2} x^{7} y^{5}   }
now factor out the second perfect square
\sqrt{ 12^{2} x^{6} X x  y^{5}  }
then factor out the second perfect square 
\sqrt{ 12^{2}  x^{6} X x  y^{4} X y}
the root of a product is equal to the product of the roots of each factor
\sqrt{ 12^{2} } \sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the first square root
12\sqrt{ x^{6} } \sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the second square root
12x³\sqrt{ y^{4} } \sqrt{xy}
reduce the index of the radical and exponent with 2 of the third square root
12x³y²\sqrt{xy}
this means that the correct answer to your question is 12x³y²\sqrt{xy} .
let me know if you have any further questions
:)
4 0
4 years ago
Last question please help((: #10
GrogVix [38]
We would use the sine function because we have an angle the hypotenuse, and the unknown opposite side.

sin(x)=opposite/hypotenuse
sin(60)=x/30
√3/2=x/30 (cross multiply)
30*√3/2=x (divide numerators and denominators by 2)
x=15√3 ft. 
So the correct answer is A

Hope this helps
6 0
4 years ago
Read 2 more answers
The mean of seven numbers is 21. Five of the numbers are 18, 23, 21, 17, and 19. One of the remaining numbers is 3/4 of the othe
zalisa [80]
Mean of a set of numbers is
(sum of the values of the numbers in the set)/(how many numbers in the set)=mean
example
1,2,4
mean is
(1+2+4)/3=7/3



ok

mean of 7 numbers is 21
(7numbers)/7=21

"5 of them are 18,23,21,17"
(mentally do 7-5=2)
2 missing
"one of the remaining is 3/4 of other"
the 2 remaining is x and 3/4x

nmow we have
(18+23+21+17+19+x+3/4x)/7=21
add like terms
(98+1 and 3/4x)/7=21
mulitply everybody by 7
98+7/4x=147
minus 98 both sides
7/4x=49
multiply both sides by 4/7 to clear fraction (7/4 times 4/7=28/28=1, so 1x=x)

1x=196/7
x=28
the other number is 3/4 of this
3/4x=3/4*28=21


the 2 unknowns are 28 arnd 21
5 0
4 years ago
Read 2 more answers
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