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kherson [118]
3 years ago
11

The length of a rectangle is twice the width. Find the width if the perimeter is 36 centimeters. Define a variable, write an equ

ation, and solve the problem.​
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

12cm

Step-by-step explanation:

1. Define the variable:

x = length of the rectangle

2x = width of the rectangle

2. Set the equation:

x + 2x is half of the rectangle

2(x + 2x) is the perimeter

So,

2(x + 2x) = 36

2x + 4x = 36

6x = 36

x = 6

Since x is the length, multiply it by 2 to find the width.

2x = 12

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Luis set up an A-frame ladder so that the angle formed between each side of the ladder and the ground is 125 degrees. What is th
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Answer:

70°

found by considering A-frame ladder as a triangle

Step-by-step explanation:

Given that,

angle form on either side of A-frame ladder with the ground = 125°(exterior)

As it is a A-frame ladder so its a triangle, we will find the angle at the top of ladder by using different properties of triangle

1) find interior angle form by A-frame ladder with the ground

125 + x = 180         sum of angles on a straight line

x = 180 - 125

x = 55°

2) find the angle on top of ladder

55 + 55 + y = 180        sum of angle of a triangle

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y = 180 - 110

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What is the proof for this?
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Knowing nexnjhdjhdhfgnu. Hngj
5 0
3 years ago
ONLY SERIOUS ANSWERS!!!! 25 POINTS
AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

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-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504±\sqrt{504^{2}-4(-153)(-135) })/2(-153)

x=(-504±\sqrt{254016-82620 })/-306

x=(-504±\sqrt{171396})/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

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