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antiseptic1488 [7]
3 years ago
8

A group of friends is sharing 2 & 1/2 pounds of berries. If each friend received 5/4 of a pound of berries, how many friends

are sharing the berries? *
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

2

Step-by-step explanation:

To get the number of friends sharing the berry, what we need to do is to divide the total pound of berries by the amount of berries each friend received.

Now it would be easier if we worked in the decimal fraction route

That means we are to divide 2.5 by 1.25

And the answer to this is just 2

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A function f is described using the information f(x) = 5x+1
lakkis [162]

Answer:

a.

i. 11

ii. 26

iii. 501

iv. 3.5

v. 5a+1

vi. 5k+6

b. x = 8

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP
creativ13 [48]

Answer:

6

Step-by-step explanation:

4/5=80%

1/8=12.5%

80÷12.5=6.4

7 0
3 years ago
A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others
Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

  • If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

  • If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0
3 years ago
If you were to draw three different parallelograms, each with a base of 6 units and a height of 4 units how would the areas comp
erma4kov [3.2K]
The areas would all be the same because they have the same side measurements.

Area = base x height

6 x 4 = 24 and will always be 24, so the area will always be 24.
3 0
3 years ago
An automobile insurance company divides customers into three categories, good risks, medium risks, and poor risks. Assume that 7
Gnom [1K]

Answer:

There is a 0.64% probability that the costumer has filed a claim.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

Our problem has these following probabilities:

-78% that a costumer is a good risk.

-20% that a costumer is a medium risk.

-2% that a costumer is a poor risk.

Also:

- 0.5% of a good risk costumer filling an accident claim

- 1% of a medium risk costumer filling an accident claim.

-2.5% of a poor risk costumer filling an accident claim.

The question is:

What is the probability that the customer has filed a claim?

P = P_[1} + P_{2} + P_{3}, in which:

-P_{1} is the probability that a good risk costumer is chosen and files a claim. This probability is: the probability of a good risk costumer being chosen multiplied by the probability that a good risk costumer files a claim. So:

P_[1} = 0.78*0.005 = 0.0039

-P_{2} is the probability that a medium risk costumer is chosen and files a claim. This probability is: the probability of a medium risk costumer being chosen multiplied by the probability that a medium risk costumer files a claim. So:

P_[2} = 0.20*0.01 = 0.002

-P_{3} is the probability that a poor risk costumer is chosen and files a claim. This probability is: the probability of a poor risk costumer being chosen multiplied by the probability that a poor risk costumer files a claim. So:

P_[3} = 0.02*0.025 = 0.0005

P = P_[1} + P_{2} + P_{3} = 0.0039 + 0.002 + 0.0005 = 0.0064

There is a 0.64% probability that the costumer has filed a claim.

4 0
3 years ago
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