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bagirrra123 [75]
3 years ago
10

Each rectangle has its area written inside and the expression mod

Mathematics
1 answer:
dangina [55]3 years ago
6 0

Answer:

Length of the boxes are 17 in, 35 in, 17 in.

Step-by-step explanation:

The given question is incomplete: please find the complete question in the attachment.

A). From Box - (1)

Area of the box = 289 in.²

Expression that denotes the area of the box = 36x² - 12x + 1

So, 36x²- 12x + 1 = 289

(6x)² - 2(6)x + (1)² = (17)²

(6x - 1)² = (17)² [ Since (a² - 2ab + b²) = (a - b)²]

Given box is a square having sides = (6x - 1) in.

∵ (6x - 1)² = 17

⇒ 6x = 18

⇒ x = \frac{18}{6} = 3

Now length of the sides = (6x - 1) = 17 in.

B) Box - (2)

Similarly, 25x²- 50x + 25 = 1225

(25x² - 50x + 25) = (35)²

(5x - 5)² = (35)²

5(x - 1) = 35 ⇒ x = 8

Here length of one side of the box is 5(x - 1) = 5(8 - 1) = 35in.

C). Box - (3)

49x² - 56x + 16 = 289

(7x)² - 2×(7x)(4) + 4²= (17)²

(7x - 4)² = (17)²

Length of each side = (7x - 4) in.

From, (7x - 4)² = (17)²

7x - 4 = 17

⇒ x = \frac{21}{7}

⇒ x = 3

Therefore, length of each side of the box = (7x - 4) = 17 in.

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Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

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E_2 = (\frac{4}{5})^{-1} = 1.25

For the next unique toy, there is now a 3 in 5 chance of getting it:

E_3 = (\frac{3}{5})^{-1} = 1.67

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

E_4 = (\frac{2}{5})^{-1} = 2.5

Finally, there is a 1 in 5 chance to get the last unique toy:

E_5 = (\frac{1}{5})^{-1} = 5

The expected number of boxes to obtain a full set is:

E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes

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3 years ago
6.
sweet-ann [11.9K]

Answer:

Step-by-step explanation:

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1

Step-by-step explanation:

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4 0
3 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

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Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

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The sum to n terms of an AP is

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2a₁ + 6d = 24 → (2)

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3 years ago
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