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loris [4]
3 years ago
7

Solve the following equation 5(y+4) =4(y+5)

Mathematics
1 answer:
kvv77 [185]3 years ago
6 0

Answer:

Step-by-step explanation:

5(y+4) = 4(y+5)

5y+20 = 4y + 20

5y = 4y

y=0

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The roots are located at (2,0) and (4,0)

In short, the roots are x = 2 and x = 4

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Find the area of the parallelogram with vertices A(−1,2,3), B(0,4,6), C(1,1,2), and D(2,3,5).
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Answer:

5*sqrt3

Step-by-step explanation:

The vector AB= (0-(-1), 4-2,6-3) AB= (1,2,3)

The modul of AB is sqrt(1^2+2^2+3^2)= sqrt14

The vector AC is (1-(-1), 1-2, 2-3)= (2,-1,-1)

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s= modul AB*modul AC*sinA= sqrt14*sqrt6* 5/ sqrt28= 5*sqrt3

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2 years ago
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