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3 years ago

8

Last winter Armand had 5/6 of a row of stacked logs. At the end of the winter he had 8/15 of the same row left how much wood did

he burn over the winter

2 answers:

RUDIKE [14]3 years ago

4 0

Answer:

$\frac{3}{10}$

Step-by-step explanation:

First we have to make the fractions even so there denominator have to be equal. So 15 times 2 gets 30 and 6 times 5 gets 30 too. Now multiply the numerator by the corresponding number of 25/30 and 16/30. Subtract to get 9/30 now simplify to get 3/10.

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

<h3>Armand burnt $\frac{3}{10}$ of wood over the winter.</h3>

Step-by-step explanation:

We know that Armand had in first place $\frac{5}{6}$ .

Then, at the end of the winter, he had $\frac{8}{15}$ .

To know how much wood he burnt, we just have to find the difference between these two quantities

$\frac{5}{6}-\frac{8}{15}=\frac{75-48}{90}=\frac{27}{90}=\frac{3}{10}$

Therefore, Armand burnt $\frac{3}{10}$ of wood over the winter.

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Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

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