Question

Last winter Armand had 5/6 of a row of stacked logs. At the end of the winter he had 8/15 of the same row left how much wood did he burn over the winter

Answer 1

Answer:

$\frac{3}{10}$

Step-by-step explanation:

First we have to make the fractions even so there denominator have to be equal. So 15 times 2 gets 30 and 6 times 5 gets 30 too. Now multiply the numerator by the corresponding number of 25/30 and 16/30. Subtract to get 9/30 now simplify to get 3/10.

Answer 2

Answer:

Armand burnt $\frac{3}{10}$ of wood over the winter.

Step-by-step explanation:

We know that Armand had in first place $\frac{5}{6}$.

Then, at the end of the winter, he had $\frac{8}{15}$.

To know how much wood he burnt, we just have to find the difference between these two quantities

$\frac{5}{6}-\frac{8}{15}=\frac{75-48}{90}=\frac{27}{90}=\frac{3}{10}$

Therefore, Armand burnt $\frac{3}{10}$ of wood over the winter.