20cm^2 assuming that each box is one cm
The sides of central angles will=always be congruent.
The sides of inscribed angles will=sometimes be congruent.
Find the separate areas.
We have a triangle with base 5 cm and height 5 cm, calculate the area:

Plug in what we know:

Multiply:

Now for the two quarter circles, we know that if we put these two together we will end up with a semi-circle with radius 5 cm. The formula for the area of a circle is:

A semi-circle is half of a whole circle, so the formula for the area of it must be:

Now plug in what we know(use 3.14 to approximate for pi):

Simplify the exponent:

Multiply:

Now add this to the area of the triangle to find the approximate area of the entire figure(round to the nearest tenth):
Answer:
O(4.-1.5) should be the answer
It’s a reflection across the x-axis