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levacccp [35]
3 years ago
5

Solve for x 2cos(x + 40 ^ 0) = 1/2 for r 0<= x<=360^ Worth 6 marks

Mathematics
1 answer:
gregori [183]3 years ago
6 0

Answer: x = 115.5°

Step-by-step explanation:

I suppose that we have the equation:

2*cos(x + 40°) = 1/2 for 0° < x < 360°

Let's solve this.

First, we isolate the cosine function:

cos(x + 40°) = (1/2)/2 = 1/4

cos(x + 40°) = 1/4

Now we can use the Acos(x) function, remember that:

Acos(cos(x)) = x

cos(Acos(x)) = x

Then if we use this function in both sides, we get:

Acos( cos(x + 40°)) = Acos(1/4)

x + 40° = Acos(1/4) = 75.5°

x = 75.5° + 40° = 115.5°

x = 115.5°

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Step-by-step explanation:

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Jan's age is 3 years less than twice Tritt's age. The sum of their ages is 30. Find their ages.
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J + t = 30
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3t - 3 = 30...add 3 to both sides
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t = 33/3
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3 years ago
The "feasible region" has vertices (4,5), (4,6), (7,4), and (3,6). If the "objective function" that you are trying to minimize i
Tanzania [10]

Answer:

The minimum value is 24

Step-by-step explanation:

we know that

The "feasible region" has vertices (4,5), (4,6), (7,4),(3,6)

The objective function is C=4x+2y

To determine the minimum value of the objective function, substitute the value of x and the value of y of each vertex in the objective function and then compare the values

1) For (4,5)

x=4,y=5

C=4(4)+2(5)=26

2) For (4,6)

x=4,y=6

C=4(4)+2(6)=28

3) For (7,4)

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4) For (3,6)

x=3,y=6

C=4(3)+2(6)=24

therefore

The minimum value is 24

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