The equivalent system of equations that would guarantee a solution of (3,-1) are
- a. (p+f)x+(q+g)y= r+h and fx+gy=h
- d. px+qy=r and (f-2p)x+(g-2q)y=h-2r
- e. px+qy+r and 5fx+ 5gy = 5h
<h3>How to determine the system of equations?</h3>
The system of equations is given as:
px +qy =r
fx + gy = h
Add both equations
(p + f)x + (q + g)y = r + h
Multiply the second equation by a constant (say 5)
5fx + 5gy = 5h
Multiply the first equation by a constant (say 2)
2px + 2qy = 2r
The combination of any of the above equations to the given equation would guarantee a solution of (3,-1)
Hence, the equivalent system of equations are (a), (d) and (e)
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Answer:
damita
Step-by-step explanation:
erin: 2/12 = 0.1666667
damita: 4/16 = 0.25
jayden: 3/15 = 0.2
0.25 is the highest concentration
He needs 4 eggs, 6 divided by 3 it 2, and 2 times 2 is 4
D is the answer to this question
Answer:
Step-by-step explanation:
A function is one-to-one if it passes the horizontal line test. This is the case if a horizontal line intersects the graph in only one place.
The graph of f(x) = x^2 - 5 is that of a parabola that opens upward. There are several possibilities here:
1. The horizontal line intersects the parabolic graph twice on the interval (-infinity,+infinity). Therefore this function is not one-to-one on this interval
(-infinity,+infinity).
2. If we define the domain as [0,+infinity), a horizontal line will intersect this parabolic graph only once. Therefore this function is one-to-one on [0,+infinity).