Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
Answer:
the answer is x>17 I hope it helps you and next time use mathpapa
Check the picture below
if that red segment, GJ, is parallel to the AE base segment of the triangle, then, the segment GJ is the midsegment of the triangle, and by the side-splitter theorem, those two triangles are similar.
Simplifying -2x + -3y = -7
Solving -2x + -3y = -7
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3y' to each side of the equation. -2x + -3y + 3y = -7 + 3y
Combine like terms: -3y + 3y = 0 -2x + 0 = -7 + 3y -2x = -7 + 3y
Divide each side by '-2'. x = 3.5 + -1.5y Simplifying x = 3.5 + -1.5y
Answer:
I think it is 1.5 or 1/2
Step-by-step explanation:
