Answer:
a) 0.59871
b) 0.22663
e) 0.95994
Step-by-step explanation:
The height of adult males on a given South Pacific Island is approximately normally distributed with mean 65 inches and standard deviation of 4 inches.
We solve using z score
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 65 inches
σ is the population standard deviation = 4 inches
a). Taller than 64 inches
This means x > 64
Hence,
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x<64) = 0.40129
P(x>64) = 1 - P(x<64) = 0.59871
b.) shorter than 62 inches
Hence,
62 - 65/4
=- 3/4 =- 0.75
P-value from Z-Table:
P(x<62) = 0.22663
c.) between 64 inches and 68 inches
Hence,
for 64 inches
64 - 65/4
=- 1/4 = -0.25
P-value from Z-Table:
P(x = 64) = 0.40129
For 68 inches
Hence,
68 - 65/4
= 3/4= 0.75
P-value from Z-Table:
P(x = 68) = 0.77337
d.) between 58 and 68 inches
e.) taller than 58 inches
Hence,
58 - 65/4
= -6/4 = -1.5
P-value from Z-Table:
P(x<58) = 0.040059
P(x>58) = 1 - P(x<58) = 0.95994
Answer:
D
Step-by-step explanation: because W in the equation is the number of weeks she paid for the self defense class. and the 12.50 would be the registration fee because that is added on top of the number of 40w.
40w + 12.50 = 492.50
-12.50 -12.50
40w = 480.00
w = 12 which is how many weeks she paid
<h3>
Answer: Choice H) 2</h3>
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Explanation:
Recall that the pythagorean trig identity is 
If we were to isolate sine, then,
We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations, 
Cosine is also positive in this quadrant.
-------------
So,
Therefore,
is an identity as long as 0 < x < pi/2
