Would a 36-ounce box for $3.72 be a better bargain than a 3-pound box for $5.36?

Bee humming birds weigh only 0.0056 ounces. They haev t eat half their body weight every day to survive. How much food does a be

Advocard [28]

Answer:

The Humming bee need to eat 0.0028 ounces of food each day.

Step-by-step explanation:

Given:

Weight of the humming bee = 0.0056 ounces

We need to find amount of food humming bee should eat each day to survive.

Solution:

Now given that:

They have to eat half their body weight every day to survive.

So we can say that;

Amount of food humming bee needs to eat is half of the weight of the humming bee.

framing in equation form we get;

Amount of food humming bee needs to eat = $\frac{1}{2}\times 0.0056 = 0.0028\ ounces$

Hence The Humming bee need to eat 0.0028 ounces of food each day.

5 0

2 years ago

I need help lololololololololololololololol

likoan [24]

Answer:

First Blank: 4*2 = 8

Second Blank: 6*2 = 12

Step-by-step explanation:

The common ratio for the right row is the number thats given on the opposite side of it's left row times 2

Hope this helps!

4 0

2 years ago

Read 2 more answers

Which is equivalent to 3sqrt8^x ?

creativ13 [48]

The correct answer is A.

7 0

3 years ago

Mike traveled to Greensboro by car. Going there took 6 hours, and the return trip was four hours. Mike averaged a speed of 81 mi

Marat540 [252]

Answer: 64.8 mph

Step-by-step explanation:

Given

Arriving time is 6 hours

return time is 4 hours

The average speed of returning 81 mph

Distance traveled while returning

$\Rightarrow d=81\times 4=324\ miles$

the average speed of the entire trip is

$\Rightarrow v_{avg}=\dfrac{2\times 324}{6+4}=\dfrac{648}{10}=64.8\ mph$

4 0

2 years ago

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

2 years ago