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xxMikexx [17]
3 years ago
14

The ratio of the radii of two similar cylinders is 3:5. The volume of the smaller cylinder is 54pi cubic centimeters. Find the v

olume of the larger cylinder.
Mathematics
1 answer:
8090 [49]3 years ago
8 0
5/3 = 1.66667

1.666666^3=4.6296 (Volume is measured in cubic units)
54x4.6396=250
250 x pi = 250Pi.
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A car drove at a rate of 32 miles every minute. If the speed per minute remains the same, which method could be used to determin
Radda [10]

Step-by-step explanation:

if the car speeds at a constant rate of 32mi/m

the number of miles travelled in the next 25 min

= 32 mi/m ×25m

800 miles in the next 25 min

5 0
3 years ago
In a circle of radius 10 cm, a sector has an area of 40 (pi) sq. cm. What is the degree measure of the arc of the sector?
Rashid [163]

Answer:

144°

Step-by-step explanation:

First, find the area of the circle, with the formula A = \pir²

Plug in 10 as the radius, and solve

A = \pir²

A = \pi(10²)

A = 100\pi

Using this, create a proportion that relates the area of the sector to the degree measure of the arc.

Let x represent the degree measure of the arc of the sector:

\frac{40\pi }{100\pi } = \frac{x}{360}

Cross multiply and solve for x:

100\pix = 14400\pi

x = 144

So, the degree measure of the sector arc is 144°

6 0
3 years ago
Read 2 more answers
Angle C is an inscribed angle of circle P. Angle C measures (-3x - 6)° and arc AB measures (-4x)° . Find x
Fynjy0 [20]
To find angle c, the fourmula is 1/2 of the intercepted arc. so, this would be (-3x-6)=(-4x)/2, then bring the 2 over, (-3x-6)2=-4x, multiply the 2, -6x-12=-4x, -2x=12, simplify, x=-6

check by plugging in.

5 0
3 years ago
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If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
5 to the power of two
Maksim231197 [3]

Answer:

25

Step-by-step explanation:

5^2 = 25

5 * 5 = 25

6 0
3 years ago
Read 2 more answers
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