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2 years ago

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The ratio of the radii of two similar cylinders is 3:5. The volume of the smaller cylinder is 54pi cubic centimeters. Find the v

olume of the larger cylinder.

1 answer:

8090 [49]2 years ago

8 0

5/3 = 1.66667

1.666666^3=4.6296 (Volume is measured in cubic units)
54x4.6396=250
250 x pi = 250Pi.

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Write the following inequality in slope-intercept form. 5x-5y>70

SCORPION-xisa [38]

The given inequality 5x - 5y > 70 when written in Slope intercept form is gotten as; y < x + (-14)

<h3>How to write slope intercept form?</h3>

The formula for equation of a line in slope intercept form is given by;

y = mx + c

where;

m is slope

c is y-intercept

We are given the inequality as;

5x - 5y > 70

Thus;

Subtract 5x from both sides to get;

-5y > 70 - 5x

divide both sides by -5 to get

y < x + (-14)

Read more about Slope Intercept Form at; brainly.com/question/1884491

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1 year ago

If (8, −9) and (6, −3) are the endpoints of the diameter of a circle, what is the equation of the circle?

Umnica [9.8K]

$(x-7)^{2} + (y+6)^{2} = 10$ is the equation of the required circle.

Step-by-step explanation:

Step 1 :

Let A = (8,-9) and B = (6,-3) be the endpoints of the diameter of the given circle.

We need to determine the circle's equation with this diameter

Step 2 :

The mid point of the diameter will be center of the required circle.

Let M = (x,y) be the mid point of the circle.

So we have x = (8+6)÷ 2 , y = ((-9) + (-3)) ÷ 2

M = ( 7, -6) is the midpoint of the diameter and the center of the circle.

Step 3 :

The radius of the circle is distance between midpoint and any one of the end point of the diameter that is distance between point A(8,-9) and M ( 7,-6)

Distance between the 2 points $(x_{1} ,y_{1}) and (x_{2} ,y_{2})$ is given by

$\sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2} }$

So distance between A(8,-9) and M ( 7,-6) = $\sqrt{(7-8)^{2}+ (-6-(-9))^{2} }$

= $\sqrt{(1)^{2}+ (3)^{2} } = \sqrt{10 }$

Hence the radius r is $\sqrt{10}$

Step 4 :

The equation of circle with center (a,b) = (7,-6) and radius r = $\sqrt{10}$ is given by

$(x-a)^{2} + (y-b)^{2} = r^{2}$

=> $(x-7)^{2} + (y-(-6))^{2} = (\sqrt{10} )^{2}$

=> $(x-7)^{2} + (y+6)^{2} = 10$ is equation of the required circle.

Step 5 :

Answer :

$(x-7)^{2} + (y+6)^{2} = 10$ is equation of the required circle.

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Mademuasel [1]

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rusak2 [61]

Answer:

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Step-by-step explanation:

x^2+9x+20

Factor

What 2 numbers multiply to 20 and add to 9

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