Answer:
its jess
here is ur ans
first option is your answer
• ANGLE 2 AND ANGLE 6 ARE CONGRUENT BECAUSE THEY ARE CORRESPONDING ANGLES.
Answer:
-1
Step-by-step explanation:
Answer:
exercising
Step-by-step explanation:
Answer:
See Below.
Step-by-step explanation:
We are given that ΔAPB and ΔAQC are equilateral triangles.
And we want to prove that PC = BQ.
Since ΔAPB and ΔAQC are equilateral triangles, this means that:
Likewise:
Since they all measure 60°.
Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:
Likewise:
Since ∠QAC ≅ ∠PAB:
And by substitution:
Thus:
Then by SAS Congruence:
And by CPCTC:
The total number of combinations without restrictions is
10 * 10 * 10 * 10 * 10 = 100000
Problem A
10 * 9 * 8 * 7 * 6 = 30240
the number of ways the combination can be set up with no repetition.
The probability of such an event is P = 30240 / 100000 = 0.3024
Problem B
The number of ways that can be done with repetition and no zeros is
9 * 9 * 9 * 9 * 9 = 59049
The probability of such an event is
P = 59049 / 100000 = 0.59049
