Given:
a varies jointly as b and c.
a=6 when b=2 and a=3.
To find:
The variation constant and the equation of variation.
Solution:
a varies jointly as b and c.
![a\propto bc](https://tex.z-dn.net/?f=a%5Cpropto%20bc)
...(i)
Where, k is the constant of proportionality.
a=6 when b=2 and a=3.
![6=k(2)(3)](https://tex.z-dn.net/?f=6%3Dk%282%29%283%29)
![6=6k](https://tex.z-dn.net/?f=6%3D6k)
![\dfrac{6}{6}=k](https://tex.z-dn.net/?f=%5Cdfrac%7B6%7D%7B6%7D%3Dk)
![1=k](https://tex.z-dn.net/?f=1%3Dk)
The value of k is 1.
Putting k=1 in (i), we get
![w=1xy](https://tex.z-dn.net/?f=w%3D1xy)
![w=xy](https://tex.z-dn.net/?f=w%3Dxy)
Therefore, the variation constant is 1 and the equation of variation is
.
Answer:
-2.82842712475
Step-by-step explanation:
x^2+10+25=27
x^2+35=27
x^2+35-27=0
x^2+8=0
8=-x^2
SQR8=-x
-SQR8=x
I don’t see the triangles srry couldn’t help
Answer:
I think its 368.28 cubic inches
Step-by-step explanation: