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2 years ago

Find the slope of a line parrallel to the line graphed

Mathematics

1 answer:

Nata [24]2 years ago

5 0

It is -2 Because it is the numBER that touches the line

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Vanessa is a caterer. She made several batches of appetizers last weekend for an event. This weekend, Vanessa made 4 times as ma

galina1969 [7]

Answer:

100 x 13/16 x 25b = 4

18 3/4 = 25b/4

b=25/4

b= 6.25

Step-by-step explanation:

25/4 = 6 1/4 last weekend and 18 3/4 this weekend.

8 0

3 years ago

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Shawn has a balance of $1200 on a credit card with an APR of 18.7%, compounded monthly. About how much will he save in interest

mina [271]

Answer:

Answer is D = 121.51

Use the Compound Interest Formula

A = P (1 + (R/12)/100)^(12*n)

Run 2 case

P = 1700

R = 18.7, R = 12.5

n = 1 (as the problem is asking over the course of a year)

Solve for A for both the R and subtract the two values of A to obtain ~121.51

Step-by-step explanation:

6 0

2 years ago

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Which of the following is not a valid triangle congruence theorem?

padilas [110]

All of them or A or b

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2 years ago

A cube with a volume of 75 cm is dilated bya factor of 5.

denis-greek [22]

Answer:

The volume of the dilated cube is 9375cm³. The volume of the original cube is 75 cm³. The scale factor for the dilation is 5. We multiply the volume of the original cube by 125 to obtain the volume of the dilated cube.

Step-by-step explanation: If thats

not right, then i am sorry, i am just getting started

7 0

3 years ago

A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

svetoff [14.1K]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals $\sqrt{20} = \sqrt{4*5} = \sqrt{4}* \sqrt{5}=2 \sqrt{5}$ (units)

Area of 1 lateral side of pyramid ABCDE is $\frac{1}{2}* 2 \sqrt{5}*x=\sqrt{5}x$

so the total lateral area is $4\sqrt{5}x$ (units squared)

and the total surface area is $20+4\sqrt{5}x$ (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is $4* \frac{1}{2}* 4 \sqrt{5} *2x=16 \sqrt{5}x$

so the total area of the second pyramid is $20+16 \sqrt{5}x$

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is $\frac{16 \sqrt{5}x}{4\sqrt{5}x} =4$ times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is $(20+16 \sqrt{5}x)-(20+4\sqrt{5}x)=12\sqrt{5}x$ units squared larger than the total area of the original pyramid.

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3 years ago

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