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3 years ago

Can you help me with 13

Mathematics

2 answers:

solmaris [256]3 years ago

6 0

Answer:

Step-by-step explanation:

Alenkinab [10]3 years ago

4 0

Answer: it would be c

Step-by-step explanation:

because she wants to make 1 and a half batches so you cut how much oatmeal she needs for one batch and you have your answer she needs 1 and a quarter cup extra

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If the force acting on an object stays the same, then the acceleration of the object is inversely proportional to its mass. If a

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3 years ago

A property contained ten acres. How many lots of not less than 50 feet by 100 feet can be subdivided from the property if 26,000

NemiM [27]

Answer:

81 lots of 5,000 square feet fits in the property.

Step-by-step explanation:

The first step is calculate the square feet of the minimum area:

$50 \: feets \times 100 \: feet = 5,000 \:square \: feet$

Second, from the ten acres we subtract the 26,000 feets of roads:

$1 \: acre = 60 \: feet \times 660\:feet = 43,560\:square\:feet\\43,560 \times 10 = 435,600\\435,600 - 26,000 = 409,600 \:square \: feet\:available$

Third, we divide the lot area over the available square feet

$\frac{409,600}{5,000} = 81.92$

81 lots of 5,000 square feet fits in the property.

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4 years ago

Which is the most appropriate unit to measure the length of a slice of pizza?

Ne4ueva [31]

A centimetre is the most appropriate unit

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4 years ago

Consider the system of linear equations.

madreJ [45]

By 4 becuase this will change the -4y to -16y , then adding the 2 equations will eliminate y.

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3 years ago

Read 2 more answers

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,

$X \sim Poi(\lambda = 10)$

1. Requires us to compute

$P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454$

2. We need to compute $P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)$

$P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454$

$P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227$

$P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757$

$P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034$

3. The expected no. of arrivals in a 15 second period is = $10 \times \frac{1}{4} = 2.5$ . So if Y be the random variable denoting number of passengers arriving in 15 seconds,

$Y \sim Poi(2.5)$

$P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821$

4. Here we use the fact that Y can take values $0,1, \dotsc$ . So, the event that "Y is either 0 or $\geq$ 1" is a sure event ( i.e it has probability 1 ).

$P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918$

3 0

3 years ago