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Nookie1986 [14]
4 years ago
14

Which interval for the graphed function contains the local

Mathematics
1 answer:
BigorU [14]4 years ago
3 0
(-5,-3) is the correct answer
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What is the answer to <br> -6x+4(-2+8y)- 2y+ 4
soldi70 [24.7K]

Answer:

− 6 + 3 0 − 4

4 0
3 years ago
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This graph represents a quadratic function. What is the function’s equation written in factored form and in vertex form?
creativ13 [48]

Answer:

Part a) The function’s equation written in vertex form is

f(x)=2(x-2)^2-8

Part b) The function’s equation written in factored form is equal to

f(x)=2x(x-4)

Step-by-step explanation:

Part a) What is the function’s equation written in vertex form?

we know that

The equation of a vertical parabola written in vertex form is equal to

f(x)=a(x-h)^2+k

where

a is a coefficient

(h,k) is the vertex

Looking at the graph

The vertex is the point (2,-8)

substitute

f(x)=a(x-2)^2-8

Find the value of the coefficient a

take one point from the graph

(0,0)

substitute in the equation

0=a(0-2)^2-8\\0=4a-8\\4a=8\\a=2

therefore

The function’s equation written in vertex form is

f(x)=2(x-2)^2-8

Part b) What is the function’s equation written in factored form?

we know that

The equation of a vertical parabola written in factored form is equal to

f(x)=a(x-x_1)(x-x_2)

where

a is a coefficient

x_1 and x_2 are the zeros or x-intercepts of the function

Remember that the x-intercept is the value of x when the value of the function is equal to zero

Looking at the graph

The zeros or x-intercepts of the function are

x=0 and x=4

so

f(x)=a(x-0)(x-4)

f(x)=ax(x-4)

Find the value of the coefficient a

take one point from the graph

(2,-8)

substitute

-8=a(2)(2-4)\\-8=-4a\\a=2

therefore

The function’s equation written in factored form is equal to

f(x)=2x(x-4)

4 0
4 years ago
Mario claims that if the dinominator of a fraction is a prime number, then its decimal form is a repeting decimal. Do you agree?
vodomira [7]

Answer:

I do not agree because Mario's claim is not general.

Step-by-step explanation:

Prime numbers: These are a set of numbers that are divisible by 1 and itself only. Examples are: 2, 3, 5, 7. 11 etc.

And a  denominator is the divisor in a given fraction.

Considering the following fractions whose denominators are prime numbers:

\frac{2}{3} = 0.66666666...

\frac{1}{7} = 0.142857142

\frac{5}{11} = 0.45454545...

\frac{3}{13} = 0.23076923

\frac{1}{7} = 0.142857142

It could be observed that Mario's claim is not a general principle which is applicable to all fractions with a prime denominator. Thus, I do not agree with his claim.

4 0
3 years ago
Please someone answer this question!
Nostrana [21]

Answer:

C) -2 ≤ x ≤ 2

Step-by-step explanation:

Domain is the set of x-values that can be inputted into function f(x).

We see that our x-values span from -2 to 2. Since they are both closed dots, we include them in the domain:

[-2, 2] or -2 ≤ x ≤ 2

7 0
3 years ago
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Can someone help me fill in the proofs and statements?
Yuri [45]

Answer:

3. they are both equvilent.

4. onl makes a right angle and mnl makes an upside down right angle.

5.makes a definition.

Step-by-step explanation:


3 0
3 years ago
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