Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer:
60x+147
Step-by-step explanation:
10(6x+15)-3
60x+150-3
60x+147
So.. take a peek at the picture... let's get two points from it, hmm say 0,4 notice it touches the y-axis there, and say hmmm -4, 1, almost at the bottom of the line
![\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 0}}\quad ,&{{ 4}})\quad % (c,d) &({{ -4}}\quad ,&{{ 1}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-4}{-4-0}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%20%28a%2Cb%29%0A%26%28%7B%7B%200%7D%7D%5Cquad%20%2C%26%7B%7B%204%7D%7D%29%5Cquad%20%0A%25%20%20%20%28c%2Cd%29%0A%26%28%7B%7B%20-4%7D%7D%5Cquad%20%2C%26%7B%7B%201%7D%7D%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%7B%7B%20m%7D%7D%3D%20%5Ccfrac%7Brise%7D%7Brun%7D%20%5Cimplies%20%0A%5Ccfrac%7B%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%7D%7B%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B1-4%7D%7B-4-0%7D)
![\bf y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad \begin{array}{llll} \textit{plug in the values for } \begin{cases} y_1=4\\ x_1=0\\ m=\boxed{?} \end{cases}\\ \textit{and solve for "y"} \end{array}\\ \left. \qquad \right. \uparrow\\ \textit{point-slope form}](https://tex.z-dn.net/?f=%5Cbf%20y-%7B%7B%20y_1%7D%7D%3D%7B%7B%20m%7D%7D%28x-%7B%7B%20x_1%7D%7D%29%5Cqquad%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Bplug%20in%20the%20values%20for%20%7D%0A%5Cbegin%7Bcases%7D%0Ay_1%3D4%5C%5C%0Ax_1%3D0%5C%5C%0Am%3D%5Cboxed%7B%3F%7D%0A%5Cend%7Bcases%7D%5C%5C%0A%5Ctextit%7Band%20solve%20for%20%22y%22%7D%0A%5Cend%7Barray%7D%5C%5C%0A%5Cleft.%20%5Cqquad%20%20%20%5Cright.%20%5Cuparrow%5C%5C%0A%5Ctextit%7Bpoint-slope%20form%7D)
once you get the slope and solve for "y", that'd be the equation of the line.
Answer:
v = m/d
Step-by-step explanation:
d = m/v
Multiply each side by v
d*v = m/v * v
dv = m
Now divide each side by d
dv/d = m/d
v = m/d