Please help, i’ll give brainliest!!!

Nicole is playing a video game where each round lasts \dfrac{7}{12} 12 7 start fraction, 7, divided by, 12, end fraction of an

Harrizon [31]

Total number of hours she schduled to play the game = 3 $\frac{3}{4}$ hours.

Let us convert mixed fraction into improper fraction

$3\frac{3}{4} = \frac{3*3+4}{4} = \frac{13}{4} \ hours.$

Duration of each round = $\frac{7}{12}$ .

In order to find the number of rounds Nicole can play, we need to divide total number of hours by duration of each round.

$\frac{13}{4}$ ÷ $\frac{7}{12}$

Converting division sign into multiplication flips the second fraction.

$=\frac{13}{4} \times \frac{12}{7}$

Crossing out 12 by 4, we get 3 on the top of second fraction.

$=\frac{13}{1} \times \frac{3}{7}$

$=\frac{39}{7} = 5.57...( Approximately).$

Because problem is about number of rounds.

So, total number of round would be 5.

5 0

3 years ago

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The sum of two numbers is 9 . one number is nine less than twice the other. find the two numbers.

dimulka [17.4K]

Hello!

To solve this problem, we will use a system of equations. We will have one number be x and the other y. We will use substitutions to solve for each variable.

x+y=9
x=2y-9

To solve for the two numbers, we need to solve the top equation. The second equation shows that x=2y-9. In the first equation, we can replace 2y-9 for x and solve.

2y-9+y=9
3y-9=9
3y=18
y=6

We now know the value of y. Now we need to find x. We can plug in 6 for y in the second equation to find x.

x=2·6-9
x=12-9
x=3

Just to check, we will plug these two numbers into the first equation.

3+6=9
9=9

Our two numbers are three and six.

I hope this helps!

7 0

3 years ago

You come home from Brian’s Orchard with a big brown bag of apples: 23 Granny Smiths, 14 Honey Crisp and 31 Red Delicious. What i

garik1379 [7]

Answer:

a. Probability of Pulling one of each = 0.03175

b. Probability of Pulling 4 Honey Crisp = 0.001797

Probability of 2 G.Smith = 0.1144

Probability of 1 Red Delicious = 0.4559

Step-by-step explanation:

Given

Granny Smiths = 23

Honey Crisp = 14

Red Delicious = 31

Required

- Probability of Pulling out one of each

- Probability of Pulling out 4 Honey Crisp; 2 Granny Smiths; 1 Red Delicious

First, the total number of apple needs to be calculated.

Total = Granny Smiths + Honey Crisp + Red Delicious

Total = 23 + 14 + 31

Total = 68

Probability of Pulling 1 of each

= P(Granny Smiths) and P(Henry Ford) and P(Red Delicious)

- Granny Smiths;

This is calculated by dividing number of Granny Smiths apples by total number of apples.

Probability = 23/68

Similarly,

Probability of Pulling Honey Crisp= Number of Honey Crisp divided by total

Probability = 14/68

Probability = 7/34

Probability of Pulling Red Delicious = Number of Red Delicious divided by total

Probability = 31/68

So, Probability of Pulling 1 of each = 23/68 * 7/34 * 31/68

Probability = 4991/157216

Probability = 0.03175

Probability of Pulling out 4 Honey Crisp;

= P(Honey) * P(Honey) * P(Honey) * P(Honey)

= (P(Honey))⁴

= (7/34)⁴

= 2401/1336336

= 0.001797

Probability of Pulling 2 Granny Smiths;

= P(Granny) * P(Granny)

= (P(Granny))²

= (23/68)²

= 529/4624

= 0.1144

Probability of 1 Red Delicious

= number of red delicious divided by total

= 31/68

= 0.4559

3 0

3 years ago

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop

attashe74 [19]

Answer:

$0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286$

$0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562$

The 99% confidence interval would be given by (0.286;0.562)

Step-by-step explanation:

Information given:

$X= 36$ represent the families owned at least one DVD player

$n= 85$ represent the total number of families

$\hat p=\frac{36}{85}= 0.424$ represent the estimated proportion of families owned at least one DVD player

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

If we replace the values obtained we got:

$0.424 - 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.286$

$0.424 + 2.58\sqrt{\frac{0.424(1-0.424)}{85}}=0.562$

The 99% confidence interval would be given by (0.286;0.562)

8 0

3 years ago

Solve for x in this equation: 3/4 + l 5-x| = 13/4<br><br> There are multiple other questions as well

omeli [17]

1. 3/4
2. im not sure if it means after taking away 3/4, but if it is, its 10/4

x=10/4 and -30/4 i believe, im not too good with fractions, sorry if its wrong :((

7 0

3 years ago

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