Whats 99 divided by eight with long divison

Mathematics

1 answer:

saveliy_v [14]3 years ago

6 0

Answer:

12 remainder 3

Step-by-step explanation:

8 times 12 is 96, and to get to 99 you would need 3 more. So it is 12 with a remainder of 3.

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Find any restrictions on x

olchik [2.2K]

The denominator of any fraction cannot be equal to zero. This is because if the denominator is equal to zero, the, the fraction itself would be "undefined".

Applying this to the above mentioned problem, we will find two denominators including the term "x". These two denominators cannot be equal to zero.

First fraction:
1/x ..................> x cannot be equal to zero

Second fraction:
1/(x^2 - 3x -4) = 1/(x - 4)(x + 1)
The denomination will be equal to zero if x = 4 or x = -1
........> x cannot be equal to 4 or -1

Based on this, the restrictions on x are as follows:
x cannot be equal to 0,4 or -1

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Instruction

slavikrds [6]

<h3>Answer: Choice C. (-x, -y)</h3>

Explanation:

Focus on one point, such as A = (1,2). Note how it moves to point A ' = (-1, -2). Both x and y coordinates have been flipped from positive to negative. The rule therefore is $(x,y) \to (-x,-y)$ . This describes a 180 degree rotation (either clockwise or counterclockwise, it doesn't matter). Points B and C follow the same idea.

Side note: Lines AA', BB' and CC' all go through the origin (0,0).

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Mr.Warner spent the most money on gas in August

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Determine the type and number of solutions of 4x^2-5x+1=0.

Arlecino [84]

<span>4x² - 5x + 1 = 0
a = 4; b = - 5, c = 1
</span>Δ = b² - 4.a.c
Δ = (-5)² - 4.4.1
Δ = 25 - 16
Δ = 9
<span>
x = - b </span>± √Δ / 2.a
$x = \frac{-5\± \sqrt{9} }{2*4}$
$x = \frac{-5\±3}{8}$
$x' = \frac{-5-3}{8} = \frac{-8}{8} = -1$
$x' = \frac{-5+3}{8} = \frac{-2}{8} (\div2) = \frac{-1}{4}$

A. Two real solutions (x' = -1 and x'' = -1/4)

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3 years ago

Whats 99 divided by eight with long divison​

Whats 99 divided by eight with long divison