Answer: u have perpendicular lines
Step-by-step explanation: Hope this helps :)
We want to find the median for the given density curve.
The value of the median is 1.
Let's see how to solve this.
First, for a regular set {x₁, ..., xₙ} we define the median as the middle value. The difference between a set and a density curve is that the density curve is continuous, so getting the exact middle value can be harder.
Here, we have a constant density curve that goes from -1 to 3.
Because it is constant, the median will just be equal to the mean, thus the median is the average between the two extreme values.
Remember that the average between two numbers a and b is given by:
(a + b)/2
So we get:
m = (3 + (-1))/2 = 1
So we can conclude that the value of the median is 1, so the correct option is the second one, counting from the top.
If you want to learn more, you can read:
brainly.com/question/15857649
Answer:
1.76
Step-by-step explanation:
Answer:
"The mean is the average of the numbers: a calculated "central" value of a set of numbers. To calculate it: add up all the numbers, then divide by how many numbers there are." -- Math is Fun
we have
![y=2x^{2} -8x+9](https://tex.z-dn.net/?f=%20y%3D2x%5E%7B2%7D%20-8x%2B9%20)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
![y-9=2x^{2} -8x](https://tex.z-dn.net/?f=%20y-9%3D2x%5E%7B2%7D%20-8x%20)
Factor the leading coefficient
![y-9=2(x^{2} -4x)](https://tex.z-dn.net/?f=%20y-9%3D2%28x%5E%7B2%7D%20-4x%29%20)
Complete the square. Remember to balance the equation by adding the same constants to each side
![y-9+8=2(x^{2} -4x+4)](https://tex.z-dn.net/?f=%20y-9%2B8%3D2%28x%5E%7B2%7D%20-4x%2B4%29%20)
![y-1=2(x^{2} -4x+4)](https://tex.z-dn.net/?f=%20y-1%3D2%28x%5E%7B2%7D%20-4x%2B4%29%20)
Rewrite as perfect squares
![y-1=2(x-2)^{2}](https://tex.z-dn.net/?f=%20y-1%3D2%28x-2%29%5E%7B2%7D%20)
-----> equation in vertex form
therefore
the answer is the option C
![y=2(x-2)^{2} +1](https://tex.z-dn.net/?f=%20y%3D2%28x-2%29%5E%7B2%7D%20%2B1%20)