Answer:
20<
Step-by-step explanation:
Answer:
0=−2
Step-by-step explanation:
espero que esto ayude! y que Dios te bendiga .. mantente a salvo!
hope this is helpful God Bless you stay safe!
Answer:
20 yards
Step-by-step explanation:
Given that:
Two Given polygons are similar :
Ratio of corresponding sides =. 1/6
Perimeter of larger polygon = 120 yards
Perimeter of smaller = p
Since they are similar, and yhe ratio of their sides Given, we use the relation :
(Smaller perimeter / larger perimeter) = (smaller side / larger side)
(p / 120) = (1 /6)
Cross multiply :
6p = 120
p = 120/6
p = 20 yards
Add up all the values shown:
64+28+52+56 = 200
This result indicates that there are 200 students total.
Of these 200 total people, there are 28 who are attending both colleges. This is the value shown in the overlapping region of the two circles.
Divide the two values (28 and 200) to get...
28/200 = 0.14 = 14%
The probability as a decimal value is 0.14 which is saying there's a 14% chance of picking someone who goes to both colleges.
Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
