The derivative of a variable raised to exponent of n, x^n is equal to the product of n and x raised to exponent of n-1.
d(x^n) = (n)(x^n-1)
So, from the given
d(9x + 5) = (1)(9x^1-0) + 5(0)
= 9
The given value of x is irrelevant to this item because the derivative does not contain any variable x.
Answer:
28.4
Step-by-step explanation:
IJ corresponds to FG, and JK corresponds to GH. So, x/6 = 52/11. 11x = 312, x = 28.36, which rounds to 28.4
Answer:
0
Step-by-step explanation:
To evaluate log10 1 without using a calculator
From the laws of logarithm,
Logₐ b = x
Then a^x = b
Therefore if log10 1 = x
10^x = 1
From the laws of indices (any figure raised to the power of 0 = 1)
a^0 = 1
Therefore, x = 0
log10 1 = 0
