10 will be your answer because 4 x 5 divided by 2 is 10
Answer:
1437.33
Step-by-step explanation:
The value of f(0) is -1
<h3>What is a function?</h3>
A function can be defined as an expression, law or rule that explains the relationship between two variables; a dependent and an independent variable.
Given the function;
f(x)= -x - 1
To determine f(0), we substitute the value of x as 0 in the function
So, we have;
f(0) = -(0) - 1
f(0) = -0 - 1
f(0) = -1
Thus, the value of f(0) is -1
Learn more about functions here:
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Answer:
The vertex form is y = (x + 4)² - 13
The minimum value of the function is -13
Step-by-step explanation:
∵ y = x² + 8x + 3
∵ 8x ÷ 2 = 4x ⇒ (x) × (4)
∴ We need ⇒ x² + 8x + 16 to be completed square
∴ y = (x² + 8x + 16) - 16 + 3 ⇒ we add 16 and subtract 16
∴ y = (x + 4)² - 13 ⇒ vertex form
∵ The vertex form is (x - a)² + b
Where a is the x-coordinate of the minimum point and b is y-coordinate of the minimum point (b is the minimum value of the function)
∴ The minimum value is -13
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
