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krek1111 [17]
3 years ago
14

A market sells oranges for $2.45. How much will 8 oranges cost?

Mathematics
2 answers:
Ulleksa [173]3 years ago
6 0

Answer:

$19.06

Step-by-step explanation:

$2.45 × 8 = $19.06

valentinak56 [21]3 years ago
3 0

Answer:

$19.60

Step-by-step explanation:

Multiply $2.45 by 8, getting $19.60.

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What is the distance between -12 and 15?
motikmotik

Answer:

27

Step-by-step explanation:

to get the distance, add -12 and 15 which gets you 27

8 0
3 years ago
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he diameter of an ice skating rink is 44 feet. In terms of π, what is the area of the rink to the nearest square yard? (9 ft2 =
crimeas [40]

Answer:

The area of the circular ring is 53.73 π  sq. yards

Step-by-step explanation:

The diameter of the skating ring = 44 ft

Diameter =  2 x Radius

⇒Radius of the ring  = 44 / 2  = 22 ft

Now, 1 ft = 0.333333 yards

⇒22 ft  = 22 x 0.333333 yards = 7.3333 yards

Now, Area of the circular Ring = \pi r^2\\

or, A = \pi (7.33)^2

=  53.73 π  sq. yards

or, the area of the circular ring is 53.73 π  sq. yards

6 0
3 years ago
What is the value of b in the equation below? StartFraction 5 Superscript 6 Over 5 squared EndFraction = a Superscript b
Margaret [11]

Answer:

B-4

Step-by-step explanation:

4 0
4 years ago
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What is 178÷2???????
Nonamiya [84]
178÷2 is 89
Hope this was helpful!
8 0
4 years ago
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Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
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