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kolezko [41]
2 years ago
10

PLEASE HELP ME!!!!!!

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
7 0

Answer:

12 inches.

Step-by-step explanation:

Length of a side of the base = 10 in.

1/2 length = 5.

s^2 = h^2 + 5^2   where s = slant height and h = height

13^2 = h^2 + 5^2

h^2 = 169 - 25 = 144

h = 12 in.

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Use Structure Tyler explained how he multiplies
aleksandrvk [35]

Answer:

The property that I would use is that however many decimal points are in the equation is the number of decimal places in the answer

Step-by-step explanation:

3 0
2 years ago
If m angle GEF is thirteen less than five times m angle DEG and m angle DEF = 149º, find m angle GEF. ​
Nina [5.8K]

Answer:

122*

122 degrees

Step-by-step explanation:

m∠GEF is 13 less than 5 times m∠DEG and m∠DEF = 149*

Solution:

As per given data,

m∠GEF = 5m∠DEG - 13* … (i)

m∠DEF = 149* -> m∠GEF + m∠DEG = 149* .. (ii)

Substituting value of m∠GEF in (ii)

We get,

(5m ∠DEG - 13*) + m∠DEG = 149*

6m ∠DEG - 13* = 149*

6m ∠DEG = 149* + 13* = 162*

m∠DEG = * = 27*

Substituting value of m∠DEG in (i)

We get,

m∠GEF = 5(27*) - 13*

m∠GEF = 135* - 13* = 122*

7 0
2 years ago
What is the sum of 4.5 × 10^8 and 8.9 × 10^8?
Andrei [34K]

Answer:

i think that the correct answer is a

Step-by-step explanation:

4 0
3 years ago
A football team lost 5 yards on each 3 plays. explain how you could use a number line to find the team's change in field positio
ollegr [7]
<span>A football team lost 5 yards on each 3 plays.
Let’s use a number line to be able to see how far in the field did they lost in 3 games.
=> 1 : 5  (1 game is to 5 yards)
=> 3 : 15 (3 games is to 15 yards )
All in all they lost 15 yards in 3 games.
pls. see attachment for more presentation.</span>



5 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
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