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s344n2d4d5 [400]
3 years ago
12

Show work to these problems

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

show work to what problems

Step-by-step explanation:

im in confusion

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What function is equivalent to g(x)=x2+15×-54
anastassius [24]

Answer:

not quite sure the specifc answer of this question at this time

Step-by-step explanation:

3 0
3 years ago
Ahh help plss!! thank u
AnnZ [28]
Basically you’re multiplying them both
(x^3 + 2x - 1)(x^4 - x^3 + 3)

so you need to make sure you multiply each one, if you do it right, you should end up with
x^7 - x^6 + 3x^3 + 2x^5 - 2x^4 + 6x -x^4 +x^3 -3

simplify by adding like terms
x^7 - x^6 + 2x^5 - 3x^4 + 4x^3 + 6x - 3

your answer would be the third option
4 0
3 years ago
In a lottery game, a player picks six numbers from 1 to 21. If the player matches all six numbers, they win 40,000 dollars. Othe
Darina [25.2K]

Answer:

The expected value of this game is -$0.26.

Step-by-step explanation:

Expected value:

Each possible earning/loss multiplied by it's probability.

Probability:

Number of desired outcomes divided by the number of total outcomes.

In this question, the order in which the numbers are chosen is not important. So we use the combinations formula to solve.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Probability of winning:

Desired outcomes:

The 6 correct numbers, so D = 6

Total outcomes:

6 numbers from a set of 21. So

T = C_{21,6} = \frac{21!}{6!15!} = 54264

Probability:

p = \frac{1}{54265}

Expected value

\frac{1}{54265} probability of earning 40,000.

\frac{54264}{54265} probability of losing 1. So

E = \frac{40,000}{54265} - \frac{54264}{54265} = -0.26

The expected value of this game is -$0.26.

7 0
3 years ago
Can someone help meeeeee???
kobusy [5.1K]
The graph is not proportional because it doesn’t go though the origin aka (0,0)
8 0
3 years ago
Read 2 more answers
A software company is releasing one of their products on a CD. The manufacturer charges a $9700 setup fee and $1.25 per CD. Appr
Gre4nikov [31]

Answer:

  about 4312

Step-by-step explanation:

You want the total cost for n CDs to be 3.50n.

The manufacturer will charge you 9700+1.25n, so you want these to be equal:

  3.50n = 9700 +1.25n

  2.25n = 9700 . . . . . . . . subtract 1.25n

  n = 9700/2.25 ≈ 4311.111...

Producing 4312 CDs will make the cost per CD slightly less than $3.50.

____

Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.

3 0
3 years ago
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