Answer:
We can use linear system of equation with one variable.
Step-by-step explanation:
It is given that,Nina is 10 years younger than Deepak.
Deepak is 3 times as old as Nina.
<u>To solve this using linear equation</u>
Let d be the age of Deepak and n be the age of NIna
we can write,
n = (d - 10) ---(1)
d = 3n
d = 3(d - 10) --------(2)
d = 3d - 30
3d - d = 30
2d = 30
d = 30/2 = 15
n - d - 10 = 15 - 10 = 5
Therefore the age of Deepak = 15 and age of Nina = 5
Answer:
m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ
Half-Life = 46.21 years.
Step-by-step explanation:
Radioactive reactions always follow a first order reaction dynamic
Let the initial mass of radioactive substance be m₀ and the mass at any time be m
(dm/dt) = -Km (Minus sign because it's a rate of reduction)
The question provides K = 0.015 from the given differential equation
(dm/dt) = -0.015m
(dm/m) = -0.015dt
∫ (dm/m) = -0.015 ∫ dt
Solving the two sides as definite integrals by integrating the left hand side from m₀ to m and the Right hand side from 0 to t.
We obtain
In (m/m₀) = -0.015t
(m/m₀) = (e^(-0.015t))
m = m₀ e^(-0.015t)) = m₀ e⁻⁰•⁰¹⁵ᵗ
m(t) = m₀ e⁻⁰•⁰¹⁵ᵗ
At half life, m(t) = (m₀/2), t = T(1/2)
(m₀/2) = = m₀ e⁻⁰•⁰¹⁵ᵗ
e⁻⁰•⁰¹⁵ᵗ = (1/2)
In e⁻⁰•⁰¹⁵ᵗ = In (1/2)
-0.015t = - In 2
t = (In 2)/0.015
t = (0.693/0.015)
t = 46.21 years
Half life = T(1/2) = t = 46.21 years.
Hope this Helps!!!
3 is my guess, tricky question tough?
Answer:
b
Step-by-step explanation:
Answer:
2x + y = 3
y = -2x + 3 <==
-2y = 14 - 6x
y = -14/2 + 6/2x
y = -7 + 3x
y = 3x - 7 <===
Step-by-step explanation:
