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Ahat [919]
3 years ago
7

Could anybody help with this confused ?!!

Mathematics
1 answer:
ss7ja [257]3 years ago
3 0
X=4 y=9

4 [times] 4-9=7
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Y=40+90x what is the meaning
Dafna1 [17]
Y = total cost
40 = The one time fee
90 = the service charge per month
x = number of months
4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!
lapo4ka [179]
Well...   the segment FG = 4x + 3, the segment GH = 7x - 12, now, the
 
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.

thus, FG = GH
or

\bf 4x+3=7x-12\implies 3+12=7x-4x\implies 15=3x
\\\\\\
\cfrac{15}{3}=x\implies \boxed{5=x}\\\\
-------------------------------\\\\
thus\qquad 
\begin{cases}
\overline{FG}=4x+3\\
4(5)+3\\
23\\
------\\
\overline{GH}=7x-12\\
7(5)-12\\
23
\end{cases}\impliedby equal\ halves
\\\\\\
\overline{FH}=23+23\implies \overline{FH}=46\implies 6y-2=46
\\\\\\
6y=46+2\implies y=\cfrac{48}{6}

and fairly sure, you know how much that is.
7 0
2 years ago
Given the following trigonometric ratio, enumerate the meaning ratio ​
Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

\sin \theta = \frac{y}{h} (1)

Cosine

\cos \theta = \frac{x}{h} (2)

Tangent

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

Cotangent

\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y} (4)

Secant

\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x} (5)

Cosecant

\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y} (6)

Where:

x - Adjacent leg.

y - Opposite leg.

h - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

h = \sqrt{x^{2}+y^{2}}

If y = AC and x = BC, then the trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

6 0
2 years ago
enrique and levi together have 386 trading cards. if enruque has 221 tradibg cards, how many does lwvi have?
mafiozo [28]
Enrique+levi=386
enrique=221
subsitute
221+levi=386
subtract 221 frm botoh sides
levi=386-221
levi=165

levi has 165 cards
4 0
3 years ago
Read 2 more answers
20 out of 60 blocks are large. What percentage of the blocks are large?
Margaret [11]

Answer:

33%

Step-by-step explanation:

20/60

6 0
2 years ago
Read 2 more answers
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