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3 years ago

How do you solve a SSS triangle?

2 answers:

7 0

1. Use The Law of Cosines first to calculate one of the angles 2. Then use The Law of Cosines again to find another angle 3. And finally use angles of a triangle add to 180° to find the last angle.

law of cosines:

cos(C) = (a^2 + b^2 − c^2)/2ab

cos(A) = (b^2 + c^2 − a^2)/2bc

cos(B) = (c^2 + a^2 − b^2)/2ca

svetoff [14.1K]3 years ago

4 0

Bye dividing one third and multiplying by pi

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Help me pls! Thnx if u do ✨✌️

daser333 [38]

Neither of them are correct. When you plug in both of the fractions into the equation, you get answers like 2/9 (from plugging in 1/3) and 1/9 (from plugging in 1/6). None of them are equal to 9.

6 0

3 years ago

Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)

kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is

ARC = [f(x2)-f(x1)]/ (x2-x1)

In case a)

f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

In case b)

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

In case c)

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0

3 years ago

Help please tell me what the answer is ASAP

Amiraneli [1.4K]

Answer:

The approximated length of EF is 2.2 units ⇒ A

Step-by-step explanation:

The tangent ratio in the right triangle is the ratio between the opposite side to the adjacent side of one of the acute angle in the triangle

In the given figure

∵ The triangle DFE has a right angle F

∵ The opposite side to angle D is EF

∵ The adjacent side to angle D is DF

→ By using the tangent ratio above

∴ tan(∠D) = $\frac{EF}{DF}$

∵ DF = 6 units

∵ m∠D = 20°

→ Substitute then in the ratio above

∴ tan(20°) = $\frac{EF}{6}$

→ Multiply both sides by 6

∴ 6 tan(20°) = EF

∴ 2.183821406 = EF

→ Approximate it to the nearest tenth

∴ 2.2 = EF

∴ The approximated length of EF is 2.2 units

7 0

3 years ago

Miles earns a 6% commission on each vehicle

slamgirl [31]

The total amount of his commission for these vehicles is $ 1686

Solution:

Given that,

Miles earns a 6% commission on each vehicle he sells

Therefore,

Commission rate = 6 %

Today he sold a truck for $18,500 and a car for $9,600

Therefore,

Commission amount = 6 % of (18500 + 9600)

Commission amount = 6 % of 28100

Calculate the above equation

$Commission\ amount = 6 \% \times 28100\\\\Commission\ amount = \frac{6}{100} \times 28100\\\\Commission\ amount = 6 \times 281 = 1686$

Thus the total amount of his commission for these vehicles is $ 1686

3 0

3 years ago

If f(x)=log2(x+4), what is f^-1(3)?

zalisa [80]

$f\left( x \right) =\log _{ 2 }{ \left( x+4 \right) } \\ \\ \log _{ 2 }{ \left( x+4 \right) } =y\\ \\ { 2 }^{ y }=x+4$

$\\ \\ x={ 2 }^{ y }-4\\ \\ \therefore \quad { f }^{ -1 }\left( x \right) ={ 2 }^{ x }-4\\ \\ \therefore \quad { f }^{ -1 }\left( 3 \right) ={ 2 }^{ 3 }-4=4$

3 0

3 years ago

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