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3 years ago

Which is the last operation performed when

Mathematics

1 answer:

gtnhenbr [62]3 years ago

3 0

The last operation to be performed would be -16 x 3. hope this helped!

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Use Lagrange multipliers to minimize the function subject to the following two constraints. Assume that x, y, and z are nonnegat

Rudiy27

Complete Question

The complete question is shown on the first uploaded image

Answer:

Option C is the correct option

Step-by-step explanation:

From the question we are told that

The equation is $f (x, y , z ) = x^2 +y^2 + z^2$

The constraint is $P(x, y , z) = x + y + z - 24 = 0$

Now using Lagrange multipliers we have that

$\lambda = \frac{ \delta f }{ \delta x } = 2 x$

$\lambda = \frac{ \delta f }{ \delta y } = y$

$\lambda = \frac{ \delta f }{ \delta z } = 2 z$

=> $x = \frac{ \lambda }{2}$

$y = \frac{ \lambda }{2}$

$z = \frac{ \lambda }{2}$

From the constraint we have

$\frac{\lambda }{2} + \frac{\lambda }{2} + \frac{\lambda }{2} = 24$

=> $\frac{3 \lambda }{2} = 24$

=> $\lambda = 16$

substituting for x, y, z

=> x = 8

=> y = 8

=> z = 8

Hence

$f (8, 8 , 8 ) = 8^2 +8^2 + 8^2$

$f (8, 8 , 8 ) = 192$

6 0

3 years ago

This year a softball coach raise $1200 for new equipment that is 4% less then he raise last year how much did he raise last year

charle [14.2K]

1200*96%
$1200 \times 0.96$

8 0

4 years ago

What value of c makes the equation true?<br> -3 – 2 ( c – 4) = 8

nevsk [136]

-3 -2c + 8 = 8
-2c = 3
C = 3/-2

7 0

4 years ago

How to solve: 30+7y =-2y-6<br>(Using linear Expression)

zhuklara [117]

Given:

The equation is

$30+7y=-2y-6$

To find:

The solution for the given equation.

Solution:

We have,

$30+7y=-2y-6$

Isolate the variable terms on the left side, we get

$7y+2y=-30-6$

$9y=-36$

$y=\dfrac{-36}{9}$

$y=-4$

Therefore, the value of y is -4.

7 0

3 years ago

The parkland zoo has a maximum calendar of 350 visitors.Write the inequality

IgorLugansk [536]

Answer: x≤350

(x=the amount of visitors)

Step-by-step explanation:

If it's a maximum, it cannot go over a certain amount, but it does not say if it could be the same amount. so use ≤

8 0

3 years ago