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Bess [88]
3 years ago
14

I NEED HELP WITH THIS ASAP THANK YOUU

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
6 0

Answer:

Step-by-step explanation:

l-7+9l= 2 The absolute value of -7+9

l-7l+9= 16 The absolute value of -7 and +9

Ilia_Sergeevich [38]3 years ago
5 0

Answer:

16 (for both)

7 + 9 = 16

7 + 9 = 16

Step-by-step explanation:

Those bars just mean the number in them CANNOT be negative

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Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you
Greeley [361]

Answer:

(f\circ g)(-5)=85

Step-by-step explanation:

We are given:

\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x

And we want to find:

(f\circ g)(-5)

This is equivalent to:

\displaystyle =f(g(-5))

So, we will evaluate g(-5) first, which yields:

\displaystyle g(-5)=(-5)^2+(-5)=25-5=20

So:

=f(g(-5))=f(20)

Then:

\displaystyle f(20)=4(20)+5=80+5=85

Therefore:

(f\circ g)(-5)=85

6 0
3 years ago
You can rewrite the trajectory equation as y = -16(x-1)^2 + 19
dsp73

I believe the answer is -16x+35

7 0
2 years ago
I NEED HELP PLEASE I'VE BEEN STUCK FOR 2 DAYS
sweet [91]

Answer:

Step-by-step explanation:

14 x 8 = 112

5 0
3 years ago
How do you solve y=3x²-6x-1 using completing the square?
Setler79 [48]
(B/2)^2 is the formula you need to complete the square
B is the second term which is -6
So let’s plug it into the formula
(-6/2)^2
(-3)^2= 9
3 0
3 years ago
what is the X co-ordinate of vertex of parabola where equation is Y is equal to X square + bx + c =\ o​
torisob [31]

Answer:

x = - \frac{b}{2}

Step-by-step explanation:

Given a quadratic equation in standard form , that is

y = ax² + bx + c = 0 ; a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

x² + bx + c = 0 ← is in standard form

with a = 1, b = b, thus

x_{vertex} = - \frac{b}{2}

4 0
3 years ago
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