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ladessa [460]
3 years ago
7

What mathematical term explicitly uses the defined term(s) line and and plane?​

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0

Answer:

c

Step-by-step explanation:

just did the assignment

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What is the additive inverse of 7/2 ?<br> A) −2/7<br> B) −7/2<br> C) 2/7<br> D) 7/2
snow_lady [41]
The additive inverse of 7/2 would be -7/2 (option B) Since its. opposite !

A)is the additive inverse of C) ; C) is the additive inverse of A) (not your answer)

B. is the additive inverse for this problem (7/2) so thats how we found that this is your answer (answer)

D is the same thing for the problem (7/2) (not your answer)

7/2 isnt the additive inverse for 7/2 because they are the SAME not the opposite.

+ = - (Positive = negative)

- = + (negative = positive)
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3 years ago
What is the answer for X+8
Alina [70]

Answer: the answer is x+8= 1

6 0
3 years ago
Ine L has equation 2x - 3y = 5. Line M passes through the point (3, -10) and is parallel to line L. Determine the equation for l
Ira Lisetskai [31]

First of all, let's find the slope of line L. To find the slope of a line, you write it in the explitic form y = mx+q, and consider the coefficient m. So, we have

2x - 3y = 5 \iff 3y = 2x-5 \iff y = \dfrac{2}{3} x - \dfrac{5}{3}

So, the slope of line L is 2/3.

Two lines are parallel if they have the same slope. So, line M has slope 2/3 as well, and we know that it passes through the point (3, -10).

When you are given the slope m and a point (x_0,y_0) of a line, its equation is given by

y-y_0=m(x-x_0)

So, if you plug your values, you have

y+10 = \dfrac{2}{3}(x-3)

which you can simplify into

y+10 = \dfrac{2}{3}x-2

y = \dfrac{2}{3}x-12

7 0
3 years ago
Find the length of the radius of the circle whose perimeter is xcm and the area is
Jobisdone [24]

\bf \stackrel{\textit{perimeter}}{\textit{circumference}}\textit{ of a circle}\\\\ C = 2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=x \end{cases}\implies x = 2\pi r\implies \boxed{\cfrac{x}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=x \end{cases}\implies x = \pi \left( \boxed{\cfrac{x}{2\pi }} \right)^2\implies x = \pi \cdot \cfrac{x^2}{2^2\pi^2}

\bf x = \cfrac{x^2}{4\pi }\implies 4\pi x = x^2\implies \cfrac{4\pi x}{x}=x\implies \blacktriangleright 4\pi = x\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since the radius is}}{r = \cfrac{x}{2\pi }}\implies r =\cfrac{4\pi }{2\pi }\implies \blacktriangleright r = 2\blacktriangleleft

6 0
3 years ago
Read 2 more answers
What would be the logical answer
nekit [7.7K]

Replace the x in the expression by 0 and work it out:-

y-intercept = 2 (0)^2 - 7(0) + 9 = 9

Answer is option  (4).

7 0
3 years ago
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