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3 years ago

Subtract.

Mathematics

1 answer:

bija089 [108]3 years ago

3 0

5x²-(-2x²) = 7x²
(-3x)-(-x) = (-3x+x)=-2x
(-2)-(10)=-12
7x²-2x-12

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The ratio of the number of picture books encyclopedias, and fairy tale books Annette had is 3:4:5 She have half of her encyclope

Flura [38]

The number of picture books does Annette have is 76 books.

Given the ratio of picture books , encyclopedias and fairy tales books is 3:4:5 and she have half of her encyclopedias to her brother and he gave her 5 books of fairytales

We need to find the number of picture books does she have

According to the statement the total number of books does Annette have is

3k+4k+5k = 12k

Where k is total number of books

Now , Picture book she have = 3/12k = 1/4k

Encyclopedia she have = 4/12k = 1/3k

Fairy tale she have = 5/12k

Here,

Encyclopedia +14 = Fairy tale

Substituting the values of Encyclopedia and Fairy tale

(1/3 -1/2)k +14 = (5/12k -5 )

Therefore.

(1/6k+14) = (5k/12-5)

Therefore,

14+5 = 5k/12 - k/6

Therefore,

19 = 3k/12

19*4=k

76 = k

Here k = 76 books

Hence the total number of picture books does she have is 76

Learn more about ratio here

brainly.com/question/2328454

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Kenya has 2 hours to make a 104 mile trip. What rate must she average to make the trip in 2 hours? A) 50 mph B) 51 mph C) 52 mph

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C. 52 mph.
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Answer:

You are right! The answer is c.

Step-by-step explanation:

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Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

$\cos \alpha = \frac{1}{\sec \alpha }$ or $\sec \alpha = \frac{1}{\cos \alpha }$

______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

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3 years ago