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4 years ago

If x varies directly as y^3 and x=2 and y=1 find x when y=5

Mathematics

1 answer:

Anit [1.1K]4 years ago

7 0

Answer:

62.5

Step-by-step explanation:

x=ky^3

2=k1^3

2=k1

k=1/2

x=1/2×5^3

x=1/2×125

x=62.5

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Can someone help me find the median of this question please.

vodomira [7]

Answer:

median = 2.8 m

Step-by-step explanation:

the median is the middle value of the data set in ascending order.

If there is no exact middle value then it is the average of the values either side of the middle.

the stem- leaf diagram shows the data in ascending order from 1.6 to 4.5

there are 10 data values so no exact middle value.

the median lies between 2.7 and 2.9

median = (2.7 + 2.9) ÷ 2 = 5.6 ÷ 2 = 2.8 m

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2 years ago

The price of a bicycle was increased from $300 to $450. What percent of the original price is the increased price?

mezya [45]

It increased with 150%

7 0

3 years ago

Help urgently pleaseee I need it now

creativ13 [48]

Answer:

$3x + 6y = 12 \\ 6y = - 3x + 12 \\ y = - 0.5y + 2 \\ m = - 0.5 \\ b = 2$

5 :

NR:

N=(-2,3)

-2×-0.5+2=1+2=3✓

R=(2,1)

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4 0

3 years ago

There is a theory that children wearing superhero costumes are more likely to harm themselves because of the unrealistic impress

____ [38]

Answer:

$Mean = 47$

$n = 6$

$s= 16.56$

$\sqrt n = 2.45$

$SEM = 11.55$

Step-by-step explanation:

Given: The above data

Solving (a): Mean of each group

Mean is calculated as:

$Mean = \frac{\sum x}{N}$

$Mean = \frac{55 + 31 + 58 + 20 + 47 + 37+68 + 32 + 85 + 69 +58 + 52+26 + 47 + 30 +35 + 53 + 43}{18}$

$Mean = \frac{846}{18}$

$Mean = 47$

Solving (b): The sample size of each group

This is the number of rows in each group.

Hence:

$n = 6$

Solving (c): Standard deviation (s)

This is calculated as:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{N}}$

So, we have:

$s= \sqrt{\frac{(55 - 47)^2 + (31 - 47)^2 +......... + (43 - 47)^2}{18}}$

$s= \sqrt{\frac{4936}{18}}$

$s= \sqrt{274.22}$

$s= 16.56$

Solving (d): Square root of n

$\sqrt n = \sqrt 6$

$\sqrt n = 2.45$

Solving (e): SEM

This is calculated as:

$SEM = \frac{s}{\sqrt N}$

$SEM = \frac{47}{\sqrt{16.56}}$

$SEM = \frac{47}{4.07}$

$SEM = 11.55$

5 0

3 years ago

Identify the equation of the parent function y=x^3 that is horizontally streched by a factor of 1/5 and reflected over the y axi

choli [55]

Answer:

$y=\frac{-x^{3}}{125}$

Step-by-step explanation:

As we know that,

<em>'Horizontal stretch, stretches the function left or right on the x-axis'. </em>

The general form of horizontal stretch is given by 'f(kx)', where 0<k<1 is the factor by which function is stretched horizontally.

Since, the function $y=x^{3}$ which is stretched by a factor of $\frac{1}{5}$ .

The new function is $y=(\frac{x}{5})^{3}$ i.e. $y=\frac{x^{3}}{125}$ .

<em>Further, the function is reflected over y-axis.</em>

That is, the reflected function is $y=\frac{(-x)^{3}}{125}$ i.e. $y=\frac{-x^{3}}{125}$ .

Hence, the required function is $y=\frac{-x^{3}}{125}$ .

7 0

3 years ago

If x varies directly as y^3 and x=2 and y=1 find x when y=5​

If x varies directly as y^3 and x=2 and y=1 find x when y=5