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3 years ago

Which is the name of a rat with endpoint A?

Mathematics

1 answer:

densk [106]3 years ago

4 0

Answer:

Step-by-step explanation:

A ray has one endpoint and the rest is a line, so AB would be the only answer that would make sense in this situation (because it's starting from A and B is a point on the ray).

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Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261$

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369$

And the 90% confidence interval would be given (0.261;0.369).

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).

lower limit =0.261

upper limit =0.369

5 0

3 years ago

Find the area of the shaded region.

olasank [31]

Area of the big triangle (shaded area and small tris for below) is 36 * 51 divided by 2 (area of triangle is base * height over 2). this would give you 918.

area of the small triangle below is 51 * 11 divided by 2 (see above), which is 280.5.

shaded shape area is the big triangle shape minus the small triangle below, which is 918-270.5, which is 637.5 units.

3 0

3 years ago

Which one is it? Plz help

Bezzdna [24]

Multiplication and division with the powers of ten

So, when multiply powers of ten, all you have to do add up the powers.

The reverse goes when you are dividing. You would subtract the powers.

9 x 10^7 => 3 x 10^3

The words " how many times as large as " indicates that we are going to divide the two, making it look like this:

$\frac{(9)(10^{7}) }{(3)(10^{3}) }$

Divide the 9 by 3 you get 3

Then subtract 10^3 from 10^7

Therefore, the answer is 3 x 10^4, or A

6 0

3 years ago

Which is an equation of the line containing the points (4, 10) and (6, 11) in standard form?

Sophie [7]

Hello,

Answer A
y-10=(11-10)/(6-4) * (x-4)
==>2y=x+16
==>-x+2y=16

8 0

3 years ago

Can anyone help me solve these linear systems using substitution?

vivado [14]

The system of the linear systems of equation using substitution is;

x = 2, y = 2
x = -20, y = -1

<h3>Linear equation</h3>

3x-y=4

x+2y=6

from (2)

x = 6 - 2y

substitute into (1)

3x-y=4

3(6 - 2y) - y = 4

18 - 6y - y = 4

- 6y - y = 4 - 18

-7y = -14

y = 2

Substitute into

x+2y=6

x + 2(2) = 6

x + 4 = 6

x = 6 - 4

x = 2

2. 2x-y= -39

x+y= -21

From (2)

x = -21 - y

substitute into

2x-y= -39

2(-21 - y) - y = -39

-42 - 2y - y = -39

- 2y - y = -39 + 42

- 3y = 3

y = 3/-3

y = -1

substitute into

x+y= -21

x + (-1) = -21

x - 1 = -21

x = -21 + 1

x = -20

3. 2x+y =11

6x-5y =9

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

6 0

2 years ago