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Akimi4 [234]
3 years ago
11

Can someone help me with this question?

Mathematics
1 answer:
kap26 [50]3 years ago
4 0

\frac{4x + 5 - 5x}{ {6x}^{2} - x - 12 }  \\  =   \frac{ - x + 5}{ {6x}^{2}  - x - 12}

The answer is the first one.

Hope this helps. - M
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Write in point-slope form an equation of the line passing through (-4, 10) and (-6, 15). Show your work.
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Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all
Stella [2.4K]

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k:

first, we can add 2 in the 3 parts of the inequality:

-18 + 2 < -k - 2 + 2 < 18 + 2

-16 < -k < 20

Now we can multiply all sides by -1, remember that this also changes the direction of the signs, then:

-1*-16 > -1*-k > -1*20

16 > k > -20

Then k can be any value between these two limits.

So the correct options (from the given ones) are:

k = -16

k = -8

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6 0
3 years ago
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Find two integers whose sum is -20 and product is 99
Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

-11+y=-20

y=-20=11=-9

when x=-9

-9+y=-20

y=-20+9=-11

so integers  are -11,-9

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3 years ago
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Which expression is equivalent to -2v+(-4)+(-3v)? A -5 B 7v C -6v+5 D -5v+ 4
inessss [21]

Answer:

-5v+4

Step-by-step explanation:

Remove the parentheses and combine the like terms:  

-2v + (-4) + 8 + (-3v)

-2v -4 + 8 -3v    [Remove parentheses]

-5v +4                [Combine like terms]

<u>-5v +4    </u>  

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