The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.
<u>Interquartile Range: </u>
Given the Data -> First Quartile = 2, Third Quartile = 5
Interquartile Range = 5 - 2 = 3
<u>Range:</u> 8 - 1 = 7
<u>Variance: </u>
We start by determining the mean,
n = number of numbers in the set
Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.
5.3
<u>Standard Deviation</u>
We take the square root of the variance,
2.3
If you are not familiar with variance and standard deviation, just leave it.
Answer:
1.98
Step-by-step explanation:
Find the number in the hundredth place 8 and look one place to the right for the rounding digit 3. Round up if this number is greater than or equal to 5 and round down if it is less than 5.
Answer: I think the answer is 12000000000
Step-by-step explanation:
To solve the problem we must know the basic exponential properties.
<h3>What are the basic exponent properties?</h3>
![\sqrt[m]{a^n} = a^{\frac{n}{m}}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Ba%5En%7D%20%3D%20a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D)
The expression can be written as ![x^9\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E9%5Csqrt%5B3%5D%7By%7D)
.
Given to us
Using the exponential property,
Using the exponential property ,
![=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}](https://tex.z-dn.net/?f=%3Dx%5E9%5Ctimes%20y%5E%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5C%3Dx%5E9%5Ctimes%20%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C%3Dx%5E9%20%5Csqrt%5B3%5D%7By%7D)
Hence, the expression can be written as .
Learn more about Exponent properties:
brainly.com/question/1807508
Answer:
15x^5*y^3
Step-by-step explanation:
